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castortr0y [4]
4 years ago
11

Part B: Find the value of G: if A = 3, b=4, and C = 5.

Computers and Technology
1 answer:
antiseptic1488 [7]4 years ago
6 0

Answer:

G=(A^3 + B) * 4-c^2

To calculate G if A=3, b=4 and C=5

cobegin

p1: A^3 = 27

P2:C^2 =25

P3: p1 +B =31

P4:P3*4 =124

P5:P4-P2 =99

coend

Explanation:

One operation is performed at a time, and on the basis of priority as we have only one processor.

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Do you think the current system of punishment in the United States works? Why? What would you change?
Simora [160]

Well the fact that jails are overcrowded is one factor that shows it's not working. Some people need help from past traumas, abuse, etc. Not everyone that acts out needs to be incarcerated, they need rehabilitation or counseling. Definitely depends on the crime committed. Therefore substance abuse users would be in rehabilitation. Even Juveniles in detention centers don't benefit from incarceration for certain offenses. There is no rehabilitation in incarceration. There are more criminals in jail and incarceration in my opinion, only for some offenders, is the last option. Now for Sex Offenders, Murderers and Criminals with violent crimes my opinion is completely opposite. Some of those offenders should be dealt with according to their crime. Also, all of the people that have been pardoned and them lessening time for drug traffickers and actual drug dealers (not necessarily users) is just a bad thing to pardon them or let them out because they don't have any violent crimes. Isn't dealing drugs, that are killing people every single day just as bad as a violent crime. In my opinion they can sit and rot for the longevity of their sentence. Some need help and I would fully support that only under some circumstances. Others I would rather not have to live amongst them.

8 0
3 years ago
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "To
SVETLANKA909090 [29]

Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

6 0
3 years ago
Write a machine-language program to add the three numbers 2, –3, and 6 and output the sum on the output device. Write it in a fo
olya-2409 [2.1K]

Answer:

Below is the code ...hope it meet the requirements

lda 0, i

adda 6, i

suba 3, i

adda 2, i

STA 0x0010 ,d

CHARO 0x0010 ,d

.end

Explanation:

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3 years ago
Analyze the following code. Which of the following statements is correct?
matrenka [14]

Answer:

that is complex wow

Explanation:

8 0
3 years ago
Def pig_latin(word): """ ------------------------------------------------------- Converts a word to Pig Latin. The conversion is
Virty [35]

def pig_latin(word):

   if word[0].lower() in 'aeiou':

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   else:

       t=''

       for x in range(len(word)):

           if word[x].lower() in 'aeiou':

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           if word[x].lower() == 'y' and x>0:

               break

           else:

               t+=word[x].lower()

       if word[0].isupper():

           word = word[len(t):]+word[:len(t)].lower()+'ay'

           word = word.title()

       else:

           word = word[len(t):]+word[:len(t)].lower()+'ay'

   return word

word = 'test'

pl = pig_latin(word)

print(pl)

I wrote my code in python 3.8. I hope this helps.

5 0
3 years ago
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