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Inessa [10]
3 years ago
5

Whoever gets this correct I’ll mark you as brainliest !!

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0
The answer should be 4 seconds.
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Cos U = 0.8829 A) 36° C) 28° B) 19 D) 41°​
11111nata11111 [884]

Answer:

28.0058078° is the answer by doing arccos of .8829 so..

5 0
3 years ago
To help solve the trigonometric inequality 2sin(x)=>-1, which two equations can be graphed?
soldier1979 [14.2K]

Answer:

B. y=sin(x) and y=-1/2

Step-by-step explanation:

We have been given the following trigonometric inequality;

2sin(x)=>-1

The above inequality can be re-written as;

sin(x)=>-1/2

after dividing both sides by 2.

We can then formulate two separate equations, one containing the expression on the right hand side and the other containing the expression on the left hand side;

From the left hand side we form the following equation;

y = sin(x)

From the right hand side we form the following equation;

y = -1/2

Therefore, the above two equations can be graphed to help solve the given trigonometric inequality

6 0
4 years ago
Find the vertex of the parabola whose equation is y=x^2+6x+2
SVETLANKA909090 [29]
(-3, 2) because you take the derivative and youll get y'=2x+6 then solve for x and that is -3 then put -3 in the original equation and you get 2
7 0
3 years ago
Find the lengths of the missing sides if side a is opposite angle a, side b is opposite angle b, and side c is the hypotenuse.
konstantin123 [22]
Hello Melissamv9321, <span>find the lengths of the missing sides if side a is opposite angle a, side b is opposite angle b, and side c is the hypotenuse</span> <span>In this right triangle, you are given the measurements for the hypotenuse, c, and one leg, b. The hypotenuse is always opposite the right angle and it is always the longest side of the triangle. To find the length of leg a, substitute the known values into the Pythagorean Theorem. Solve for a2.</span>

3 0
4 years ago
Find three consecutive odd integers such that three times the square of the first integer is twelve more than the product of the
7nadin3 [17]
Consecutive odd integers are 2 apart
they are
n,n+2,n+4


3(n²)=12+(n+2)(n+4)
expand
3n²=12+n²+6n+8
3n²=n²+6n+20
minus n² both sides
2n²=6n+20
divide bot sides by 2
n²=3n+10
minus 3n+10 both sides
n²-3n-10=0
factor
(n-5)(n+2)=0
n-5=0
n=5

n+2=0
n=-2
has to be odd, so no


n=5
n+2=7
n+4=9


the integers are 5,7,9
4 0
3 years ago
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