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4 years ago

If the input is -8, what was the output

Mathematics

1 answer:

Diano4ka-milaya [45]4 years ago

5 0

Answer:

I think the output can be any numbers because you don't have the function to put -8 in, so I can't identify the output exactly is.

Step-by-step explanation:

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How do I do this delta math question?

KonstantinChe [14]

It does not represent a polynomial

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3 years ago

Which equation demonstrates the distributive property?

Oliga [24]

Answer: 3(n-2) =3n-6

Step-by-step explanation: There all separate groupings

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3 years ago

A glass of skim milk supplies 0.1 mg of iron, 8.5 g of protein, and 1 g of carbohydrates. A quarter pound of lean red meat provi

Tems11 [23]

Answer:

glasses of milk=4

quatar pounds servings of meat =5

two slices of whole grains bread =8

Step-by-step explanation:

Let m= milk

r=meat

b=bread

0.1m+3.4r+2.2b=35 (1)

8.5m+22r+10b=224 (2)

m+20r+12b=200 (3)

Multiply (1) by 85 and (2) by 1

8.5m+289r+187b=2,975 (4)

8.5m+22r+10b=224 (5)

Subtract (5) from (4)

267r+177b=2,751 (6)

Recall,

8.5m+22r+10b=224 (2)

m+20r+12b=200 (3)

Multiply (2) by 1 and (3) by 8.5

8.5m+22r+10b=224 (7)

8.5m+170r+102b=1700 (8)

Subtract (7) from (8)

148r+92b=1,476 (9)

Recall,

267r+177b=2,751 (6) and

148r+92b=1,476 (9)

Multiply (6) by 148 and (9) by 267

26196b=407,148 (10)

24564b=394,092 (11)

Subtract (11) from (10)

1,632b=13,056

Divide both sides by 1,632

b=13,056/1,632

b=8

Substitute the value of b in (9)

148r+92b=1,476 (9)

148r+92(8)=1,476

148r+736=1,476

148r=1,476-736

148r=740

Divide both sides by 148

r=740/148

r= 5

Substitute the value of b and r in (1)

0.1m+3.4r+2.2b=35 (1)

0.1m+3.4(5)+2.2(8)=35

0.1m+17+17.6=35

0.1m+34.6=35

0.1m=35-34.6

0.1m=0.4

Divide both sides by 0.1

m=0.4/0.1

m=4

4 glasses of milk, 5 quatar pounds servings of meat and 8 two slices of whole grains bread will supply the required nutrients.

8 0

4 years ago

Alana biked 45 miles in 3 hours how many miles did she bike in 1 hour

alisha [4.7K]

15mph. 45/3=15 . She biked 15 miles per hour .

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago