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3 years ago

Which describes the amount of product the customers want to buy?

Mathematics

2 answers:

FromTheMoon [43]3 years ago

3 0

Answer:

Demand

Step-by-step explanation:

Supply is what the stores have and demand is what the customers want

joja [24]3 years ago

3 0

Answer:B

Step-by-step explanation:

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Examine the diagram. It is not drawn to scale.

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119 as c=62 A=61 so

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2 years ago

Gregorio took two tests. Find his z-score for each test. (Remember: The number of standard deviations between a score and the me

never [62]

I found the missing parts of this question.
Test A
Gregorio’s score 62 
Mean score 80 
Standard deviation 6 

Test B 
Gregorio's score 70 
Mean score 90 
Standard deviation 10 

a. Test A: 3; Test B: 2; Test A 
c. Test A: –2; Test B: –3; Test A 
b. Test A: –3; Test B: –2; Test B 
d. Test A: –3; Test B: –2; Test A


Refer to the attachment for the formula of z score:

test A: z = (62-80)/6 = -18/6 = -3
test B: z = (70-90)/10 = -20/10 = -2

B. Test A: –3; Test B: –2; Test B

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3 years ago

HELP!!!In the expression 100 a/b, if a is greater than b, which statements are true? b ≠ 0. Select all that apply.

MAXImum [283]

Answer:

$\large\boxed{\text{The expression is equal to}\ \sqrt[b]{100^a}}\\\boxed{\text{The expression is greater than 100}}$

Step-by-step explanation:

$a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\text{True statement:}\\\\100^\frac{a}{b}=\sqrt[b]{100^a}\\\\a>b\to\dfrac{a}{b}>1\to\dfrac{a}{b}=1\dfrac{a-b}{b}\\\\100^\frac{a}{b}=100^{1\frac{a-b}{b}}=100^{1+\frac{a-b}{b}}=100^1\cdot100^\frac{a-b}{b}=100\sqrt[b]{100^{a-b}}\\\\a>b\to a-b>0\to100^{a-b}>1\\\\\text{Therefore}\ 100\sqrt[b]{100^{a-b}}>100$

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3 years ago

Todea what did one pencil say to another mathematics algebra order of operations answer

Serjik [45]

Part 1

$6- \frac{18-3^2}{4+(2-3)} =6- \frac{18-9}{4+(-1)} \\ \\ =6- \frac{9}{4-1} =6- \frac{9}{3} =6-3 \\ \\ =3$

Part 2

$7-8\div4(3^2-1)=7-8\div4(9-1) \\ \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\ \\ =6 \frac{1}{2} = \frac{13}{2}$

Part 3

$2-2(2-5)^2+3^2=2-2(-3)^2+9 \\ \\ =2-2(9)+9=2-18+9=-7$

Part 4

$(5^2-9\cdot3)^2-11=(25-27)^2-11 \\ \\ =(-2)^2-11=4-11=-7$

Part 5

$[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\ \\ =(1-5)\cdot4=-4\cdot4=-16$

Part 6

$12-11\cdot2+16\div8=12-22+2 \\ \\ =-8$

Part 7

$-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\ \\ =-2-(-1)=-2+1=-1$

Part 8

$8+2\cdot3-14\div7=8+6-2 \\ \\ =12$

Part 9

$(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\ \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\ \\ =36+4=40$

Part 10

$7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\ \\ =7+(-7)\cdot5=7+(-35)=7-35 \\ \\ =-28$

Part 11

$3-2[2^3+(-1)^3]=3-2[8+(-1)] \\ \\ =3-2(8-1)=3-2(7)=3-14 \\ \\ -11$

Part 12

$18+6\div3(2^2+5)=18+6\div3(4+5) \\ \\ =18+6\div3(9)=18+6\div27=18+ \frac{2}{9} \\ \\ =18 \frac{2}{9}$

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3 years ago

Tyler has ten coins. Each coin weighs two hundred thirty-one thousands of an ounce. Decide if each expression is equivalent to t

White raven [17]

The answers that you have circled are correct

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3 years ago

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