Consider the equation
1) First row of the table
Set x=0 and solve as follows:
The answer is y=20 and the pair x-y is (0,20)
2) Second row
Set x=1 and solve, as follows:
The answers are y=10 and (1,10)
3) Third row.
Set y=0 and solve as follows:
The answers are x=2 and (2,0)
The equation is y=mx+c
C=8
M=-1
Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
Answer:oop
Step-by-step explanation:
X^2 = 7^2 + 24^2x^2 =49 + 576x^2 = 625
x = 25
