8c + 6-3c -2
8c -3c + 6-2 = 5c + 4
Brainliest please!
So this first wants you to find where sin is √3/2 when θ is between π and 3π/2. θ would therefore be located at 2π/3.
Now plug in the value of θ for cosine:
cos (2π/3) = -1/2
And tangent:
tan (2π/3) = -√3/3
Answer:
<em>π/2 and π/3</em>
Step-by-step explanation:
Given the equation 2cos²x - cosx = 0, to find the solution to the equation, we will follow the following step.
let P = cosx
The equation becomes 2P²-P = 0
P(2P-1) = 0
P = 0 and 2P-1 = 0
P= 0 and P = 1/2
Since P = cosx
cosx = 0 and cos(x) = 1/2
If cos(x) = 0
x = cos⁻¹0
x = 90⁰
x = π/2
If cos(x) = 1/2
x = cos⁻¹1/2
x = 60⁰
x = π/3
<em>Hence the solutions to the equation are π/2 and π/3.</em>
Total amount of money in the savings account after 11 weeks is $1310.
Total money in the account =
Initial Money + Money added per week x Number of weeks
Given:
Initial Money = $650
Money added per week = $60
Total money in the account = S
Number of weeks = W
Substituting it in the above equation we get,
S = $650 + $60xW (General Equation)
Total amount of money in the savings account after 11 weeks
S = $650 + $60x11
S = $650 + $660
S = $1310
Thus total amount of money in the savings account after 11 weeks is $1310.
Learn more about Linear Equations here :
brainly.com/question/2263981
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Answer:
C. 17, 12, 7
Step-by-step explanation:
In a triangle, the sum of the lengths of any two sides must be greater then the length of the third side. If you can show any two segments, the sum of whose lengths is less than the length of the third segment, that cannot form a triangle.
In choices A, B, and D, there is at least one sum of the lengths of two segments that is less then the length of the third segment. That shows that choices A, B, and D cannot form triangles.
A. 8 + 7 = 15 < 16 No
B. 9 + 7 = 16 = 16 No
D. 11 + 5 = 16 < 17 No
C.
17 + 12 = 29 > 7
12 + 7 = 19 > 17
17 + 7 = 24 > 12
Yes