94 seats
There are 2 ways to do this one:
1. 18 x 3 = 54
54 + 40 = 94
2. 40 + 3 + 3 + 3.... and so on.
Let me know if this was helpful!
Answer: (a) ![e^3](https://tex.z-dn.net/?f=e%5E3)
(b) ![e^{10}](https://tex.z-dn.net/?f=e%5E%7B10%7D)
(c) ![\dfrac{1}{e^4}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Be%5E4%7D)
(d) ![e^{4}](https://tex.z-dn.net/?f=e%5E%7B4%7D)
Step-by-step explanation:
Properties of exponents :
1) ![a^m\times a^n=a^{m+n}](https://tex.z-dn.net/?f=a%5Em%5Ctimes%20a%5En%3Da%5E%7Bm%2Bn%7D)
2) ![\dfrac{a^m}{a^n}=a^{m-n}](https://tex.z-dn.net/?f=%5Cdfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D)
3) ![(a^m)^n=a^{mn}](https://tex.z-dn.net/?f=%28a%5Em%29%5En%3Da%5E%7Bmn%7D)
4) ![a^{-n}=\dfrac{1}{a^n}](https://tex.z-dn.net/?f=a%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Ba%5En%7D)
Now , we simplify the given expression using the above properties.
a) ![(e^6)(e^{-3})](https://tex.z-dn.net/?f=%28e%5E6%29%28e%5E%7B-3%7D%29)
[By property (1)]
[∵ (+)(-)=(-)]
b) ![(e^{-2})^{-5}](https://tex.z-dn.net/?f=%28e%5E%7B-2%7D%29%5E%7B-5%7D)
[By property (3)]
[∵ (-)(-)=(+)]
c) ![(\dfrac{e^6}{e^2})^{-1}](https://tex.z-dn.net/?f=%28%5Cdfrac%7Be%5E6%7D%7Be%5E2%7D%29%5E%7B-1%7D)
[By property (2)]
[By property (4)]
d) ![(e^3)^{\frac{4}{3}}](https://tex.z-dn.net/?f=%28e%5E3%29%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D)
[By property (3)]
Hi rainy here !!! so lets see lets set up your problem like this
X/1280 = 60%/100 so lets cross multiply
100 times X =100X
60 times 1280 = 76800
100X=76800 now lets divide each side by 100
100 divided by 100 = 0
76800 divided by 100 = 768
X=768
So now we have to subtract to get the total amount so 1280 minus 768 = 512
512 is your answer :)
Hope I helped if u have any questions on how I did your problem feel free to message me or comment on my page bye !!!
Love ~Rainy~
840 6 digit pin codes are possible! Please mark brainlest
17 1/4 because I did addition.