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2 years ago

8

The ratio of the surface area of two cylinders is 1:9. The smaller cylinder has a radius of 3 inches and a height of 4 inches. W

hat are the dimensions of the larger cylinder?

1 answer:

lana66690 [7]2 years ago

3 0

You need to multiply them 3-4 and get 12 so that's part of your answer

then you make it 12:9.

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Graph y=2/3x-4<br><br><br><br> i need help!!!!!

Irina18 [472]

Step-by-step explanation:

Y=2/3x-4 is in Slope - intercept form meaning you are shown the slope (how steep the line is) and the y intercept (where the equation hits the vertical axis)

With the given information, select the point (0, -4) on the graph, this is where the line crosses the y axis, as shown through the -4 in the equation.

Next, look at the slope and youll see 2/3x. Slope is in format "rise over run" meaning the first number (2) is the vertical change, so up two, and the second number (3) is horizontal change, right 3.

Combine these two steps together and select point (0. -4) then the next point should be at (3,2), 2 units up and three to the right from the y intercept.

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vfiekz [6]

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3 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

<u>Algebra I</u>

Factoring

<u>Calculus</u>

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

<u>Step 2: Differentiate Pt. 1</u>

<em>Find 1st Derivative</em>

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate <em>y'</em> terms: $-xy' - 2y' = y$
[Algebra] Factor <em>y'</em>: $y'(-x - 2) = y$
[Algebra] Isolate <em>y'</em>: $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

<u>Step 3: Find </u><em><u>y</u></em>

Define equation: $-xy - 2y = -4$
Factor <em>y</em>: $y(-x - 2) = -4$
Isolate <em>y</em>: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

<u>Step 4: Rewrite 1st Derivative</u>

[Algebra] Substitute in <em>y</em>: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

<u>Step 5: Differentiate Pt. 2</u>

<em>Find 2nd Derivative</em>

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

<u>Step 6: Find Slope at Given Point</u>

[Algebra] Substitute in <em>x</em>: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

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3 years ago

Read 2 more answers

Can yall help me with this onee??

umka21 [38]

Answer:

Ok so it's been a minute since I've done this however the answer would be A I think.

3x+2y=3
subtract 3x and put it behind 2y
divide by 2 throughout the entire equation
subtract 1 3/2 on both sides of the equation
you should get y=0

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3 years ago

The slope between two points found in quadrant I is always positive

Pani-rosa [81]

Yes that is the correct answer

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3 years ago