Answer:
Option b 18x-8 is correct answer.
Step-by-step explanation:
We need to simplify the expression 4(3x – 2) + 6x(2 – 1) and find the result.
Solving:
= 4(3x – 2) + 6x(2 – 1)
Multiplying terms with values in the bracket.
= 12x - 8 + 12x -6x
Adding like terms
= 12x + 12x - 6x -8
= 24x -6x -8
= 18x -8
So, Option b 18x-8 is correct answer.
The answer will be: Y = -2/5x - 4
Slope intercept form: y= Mx+b
You find the slope (M) using: rise/run formula
You find (b) by looking at the y-intercept
Answer:
Okay so for finding the equation of a line, which is a function, the equation is set to y, so you can eliminate A and B. When the slope of an equation is 0, we are saying that the y value of any point of the line is going to be the same, which is 9 from the given point (2,9).
So the answer is C. y=9
Step-by-step explanation:
Answer:
Step-by-step explanation:
In this particular case we have the following system of equations:
y
=
−
3
x
+
4
[
E
q
.
1
]
x
+
4
y
=
−
6
[
E
q
.
2
]
Substituting
[
E
q
.
1
]
in
[
E
q
.
2
]
:
x
+
4
(
−
3
x
+
4
)
=
−
6
Applying the distributive property on the left side:
x
−
12
x
+
16
=
−
6
Simplifying
:
−
11
x
=
−
22
Solving for
y
:
x
=
−
22
−
11
=
2
Substituting
x
=
2
in
[
E
q
.
1
]
:
y
=
−
3
(
2
)
+
4
=
−
2
Therefore
, the solutions are
x
=
2
and
y
=
−
2
Answer: The required length of the segment AA' is 11 units.
Step-by-step explanation: Given that the point A(5, 11) is reflected across the X-axis.
We are to find the length of the segment AA'.
We know that
if a point (x, y) is reflected across X-axis, then its co-ordinates becomes (x, -y).
So, after reflection, the co-ordinates of the point A(5, 11) becomes A'(5, -11).
Now, we have the following distance formula :
The DISTANCE between two points P(a, b) and Q(c, d) gives the length of the segment PQ as follows :

Therefore, the length of the segment AA' is given by

Thus, the required length of the segment AA' is 11 units.