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Eddi Din [679]
3 years ago
8

Is (4, 4) a solution of the graphed system of inequalities?answers are A) Yes B) No​

Mathematics
1 answer:
Softa [21]3 years ago
8 0

Answer: A) Yes

If (4, 4) lies within the double-shaded area that covers the solution set of both inequalities, then it's a solution.

It does, therefore, it's a solution to the system of inequalities.

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Peter attends 6 lessons each week . A year he attends 52 weeks. But he missed 5 classes how many lessons did he attend during th
VMariaS [17]
You are given the information that he takes six lessons per week. First we will calculate the total lessons he could potentially take per year.

6 • 52 = 312

He could potentially take 312 lessons in one year.

Now that you know this information, you simply subtract the days he missed from that total.

312 - 5 = 307

Your final answer: Peter took 307 lessons during the year.
4 0
3 years ago
A garden wall is 4 feet in height and has a 6-foot shadow. A tree in the garden casts a 24-foot shadow at the same time of day.
4vir4ik [10]

Answer:

7height

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
During a​ sale, a dress is marked down from a selling price of ​$80 to a sale price of ​$60. What is the percent​ markdown
Zanzabum
$80 x .25 = 20

$80-20=$60

25% markdown
5 0
3 years ago
What is the approximate diameter of a tire that will make 775 complete rotations in one mile? (Note: there are 5280 feet
GalinKa [24]

Answer:

About 2.17 feet.

Step-by-step explanation:

Let <em>d</em> represent the diameter of the tire.

Then the circumference of the tire will be:

C=d\pi

So, the tire will travel dπ miles after one rotation.

After 775 rotations, the total miles traveled should be 5280 feet. Thus:

775(d\pi)=5280

Solve for <em>d:</em>

<em />\displaystyle d=\frac{5280}{775\pi}<em />

Approximate:

d=2.1686...\approx2.17

The circumference of the tire should be about 2.17 feet.

5 0
2 years ago
From first principle find the derivative of logx​
Archy [21]

Hello!

\large\boxed{\frac{dy}{dx}logx = \frac{1}{xln10}  }

Recall that:

logx can be rewritten as:

log_{10}x

Use the equation for the derivative of a log expression:

\frac{dy}{dx}log_{a}u = \frac{1}{ulna} * u'

Substitute in the values in the expression:

logx = \frac{1}{xln10} * 1 = \frac{1}{xln10}

4 0
3 years ago
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