Answer:
True sorry if I’m wrong
Step-by-step explanation:
Answer:
...
Step-by-step explanation:
Find the value of -6(-2)^2 - 4^2 - 3(-2x^4).
-6(-2)^2 - 4^2 - 3(-2x^4)
Multiply -6(-2)^2.
12^2 - 4^2 - 3(-2x^4)
Subtract 12^2 and -4^2.
8 - 3(-2x^4)
Distribute -3(-2x^4).
8 + 6x^4
Therefore the value of 6(-2)^2 - 4^2 - 3(-2x^4) is 8 + 6x^4.
-9x^3-72x^2+36=3x^3+x^2-3x+8 Add 9x^3 to both sides.
-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8 Add 72x^2 to both sides
36 = 12x^3 + 73x^2 - 3x + 8 Subtract 36 from both sides.
0 = 12x^3 + 73x^2 - 3x - 28
It does factor, but it is not very nice.
(x + 6.06)(x - 6.09)(x + 0.632)
If there is any kind of error please report it in a note below.