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3 years ago

What is the measurement 345.067 mg rounded to four significant digits?

Mathematics

2 answers:

Studentka2010 [4]3 years ago

7 0

significant digits start at the first nonzero number, so 345.067 to four digits is 345.1

The answer is A.

Viktor [21]3 years ago

4 0

count four from the first digit to the fourth one. When you see the fourth one, look at the digit after. if it is 5+ then the fourth digit increases by one. if 5- then it stays the same. 6>5 so 0 becomes 1.

Therefore the answer is 345.1mg

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Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Write an expression for the calculation the difference of the products of 5 and 2 and 5 and 1

oee [108]

Let's review the terminology. A product is what you get when you multiply two numbers. So, the product of 5 and 2 is basically "5*2," and the product of 5 and 1 is "5*1."

The difference means when you subtract one from the other. So, the difference of 5*2 and 5*1 means "(5*2)-(5*1)". (Note: I put in parentheses to make sure the reader understands that 5*2 is separate from 5*1. 5*2-5*1 is confusing: you might not know what to do first!)

So, "(5*2)-(5*1)" can be your answer, OR you can simplify it further by actually doing the multiplication: "10-5". If you want the answer, just subtract--the expression is equal to 5.

Answer: "(5*2)-(5*1)" OR "10-5" OR "5"

3 0

3 years ago

4x ²-1= HELP ME FAST IF ITS RIGHT ILL GIVE YOU BRAINLEIST !!!!!!

snow_tiger [21]

Answer:

(2x+1)(2x−1)

Step-by-step explanation:

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3 years ago

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alex41 [277]