Step-by-step explanation:
the midpoint between 2 points (x1, y1) and (x2, y2) is simply ((x1+x2)/2, (y1+y2)/2).
so,
1.
(9, 7) to (4, -3)
midpoint is ((9+4)/2, (7+ -3)/2) = (13/2, 4/2) = (6.5, 2)
2.
(-7, -5) to (2, 1)
midpoint is ((-7+2)/2, (-5+1)/2) = (-5/2, -4/2) = (-2.5, -2)
3.
now we have the midpoint and need the second point.
(4, 2) over (3, 4) to (x, y)
3 = (4 + x)/2
6 = 4 + x
x = 2
4 = (2 + y)/2
8 = 2 + y
y = 6
4.
(-2, 1) over (-3, 2) to (x, y)
-3 = (-2 + x)/2
-6 = -2 + x
x = -4
2 = (1 + y)/2
4 = 1 + y
y = 3
40 I'm not quite sure but I think that might be the ANWSER!
we know that
If V is the midpoint of SU
then
SV=VU
substitute the given values
2x+18=8x-6
solve for x
8x-2x=18+6
6x=24
<h2>x=4</h2>
Find SV
SV=2x+18
SV=2(4)+18
<h2>SV=26 units</h2>
so
<h2>VU=26 units</h2>
and
SU=2SV
SU=2(26)
<h2>SU=52 units</h2>
The answer would be 36.
Following PEMDAS, you'd solve what's in the parenthesis first. 2^2 = 4 and 3^2 = 9. This leaves you with 10 + (4 + 9) x 2. Add 9 and 4 to get 13, and then the parenthesis are done.
Next, you'd multiple 13 and 2 (since it's the next step in PEMDAS) to get 26.
Finally, you add together 10 and 26 to get the answer, which is 36.
I hope this helps!
