1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
Answer: Somewhat.
Explanation: Try refreshing your pages, or reopening your browser.
A software-based <u>Firewall</u> is dedicated to examining and blocking internet traffic.
Answer:
Please see the attached file for the complete answer.
Explanation:
The type of physical drives does windows disable defragmenting, but provides another method of optimization is known as windows.
<h3>What is windows?</h3>
It should be noted that windows is a separate viewing area on a computer display screen in a system.
In this case, the type of physical drives does windows disable defragmenting, but provides another method of optimization is known as windows.
Learn more about window on:
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