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beks73 [17]
3 years ago
5

Help please?

Mathematics
2 answers:
kakasveta [241]3 years ago
4 0
(3.5 x 10^-5)(3 x 10^-10) = (3.5 x 3) x 10^(-5 - 10) = 10.5 x 10^-15 = 1.05 x 10(1 - 15) = 1.05 x 10^-14
kolbaska11 [484]3 years ago
4 0
B . 1.05 x 10^-14
hope i helped

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(20 x 40) x 14 = ?
fredd [130]

To solve this problem, we must use the order of operations outlined by PEMDAS, which tells us that we should simplify or compute parentheses first, then exponents, multiplication, division, addition, and finally subtraction.

Using this method, we have to perform the multiplication inside the parentheses first.

(20 * 40) * 14

800 * 14

Finally, we must perform the final operation to simplify this expression, which is multiplication.

800 * 14 = 11200

Therefore, your final answer is 11200.

Hope this helps!

3 0
3 years ago
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Tools
const2013 [10]

Answer:just do the math mate

Step-by-step explanation:

6 0
3 years ago
What is the distance between -6 and -3 on a number line?
Ira Lisetskai [31]
I think it's 3 but idk I'm not good at math
7 0
3 years ago
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Question: How long does it take an investment to quadruple in value if it earns 4% simple interest per year?
Assoli18 [71]

Answer:

It takes 75 years for the investment to quadruple in value

Step-by-step explanation:

Simple Interest

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

T = E + P

In this question:

4% simple interest per year, so I = 0.04.

Quadruple:

t when T = 4P.

The interest earned is:

T = E + P

4P = E + P

E = 3P

Now we find the time.

E = P*0.04*t

3P = P*0.04*t

0.04t = 3

t = \frac{3}{0.04}

t = 75

It takes 75 years for the investment to quadruple in value

7 0
2 years ago
2. A statistics student plans to use a TI-84 Plus calculator on her final exam. From past experience, she estimates that there i
Anarel [89]

Answer:

  1. P(≥1 working) = 0.9936
  2. She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.

Step-by-step explanation:

1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...

... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936

2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.

If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.

This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.

_____

My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)

7 0
3 years ago
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