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Nikitich [7]
3 years ago
11

Graph the equation to solve the system y= -1/2x +3 y= -1/3x +4

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0

Answer:

the solution is (-6, 6)

Step-by-step explanation:

This system, y= -1/2x +3 y= -1/3x +4, can be quickly solved for x by letting y = y:

y= -1/2x +3    =   y= -1/3x +4.  Then -1/2x + 3 = -1/3x +4.  The fractional coefficients should be enclosed inside parentheses:

(-1/2)x + 3 = (-1/3)x +4

Let's remove the fractional coefficients.  The LCD is (2)(3) = 6.  Multiply all four terms by 6, obtaining:

-3x + 18 = -2x + 24

Combining like terms, we get -6 = x.  

Find y:  substitute -6 for x in either of the given equations:

y= (-1/2)(-6) +3  =  3 + 3 = 6.  So y = 6 when x = -6, and the solution is (-6, 6).

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Answer:

D : 510 units

Step-by-step explanation:

NOTE:

Something to consider when solving problems like this is to break the large shape down into smaller, more managable shapes. So for this problem, you can break down this irregular shape into two rectangles. This will make solving problems similar to this easier in the future :)

WORK:

I broke down this shape into two rectangles with the following dimensions:

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You also know that the depth has to be 5 feet (the problem itself did not account for differences in feet and meters, as when I converted the 5 feet to meters and solved that way, none of the answers were correct)

Using this information, you can now solve for the volume of each of the rectangles

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2 years ago
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STALIN [3.7K]

Number 1: (-1+2i)+(6-9i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(-1+6\right)+\left(2-9\right)i\\=5-7i

Number 2: (3-3i)-(4+7i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(3-4\right)+\left(-3-7\right)i\\Refine\\=-1-10i

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Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(-5-2\right)+\left(2+8\right)i\\Refine\\=-7+10i

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