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Nikitich [7]
3 years ago
11

Graph the equation to solve the system y= -1/2x +3 y= -1/3x +4

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0

Answer:

the solution is (-6, 6)

Step-by-step explanation:

This system, y= -1/2x +3 y= -1/3x +4, can be quickly solved for x by letting y = y:

y= -1/2x +3    =   y= -1/3x +4.  Then -1/2x + 3 = -1/3x +4.  The fractional coefficients should be enclosed inside parentheses:

(-1/2)x + 3 = (-1/3)x +4

Let's remove the fractional coefficients.  The LCD is (2)(3) = 6.  Multiply all four terms by 6, obtaining:

-3x + 18 = -2x + 24

Combining like terms, we get -6 = x.  

Find y:  substitute -6 for x in either of the given equations:

y= (-1/2)(-6) +3  =  3 + 3 = 6.  So y = 6 when x = -6, and the solution is (-6, 6).

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Answer:

x>7

Step-by-step explanation:

6 0
2 years ago
Express 3500 in scientific notation that indicates it has two significant digits
arsen [322]

Hey there!

“3500 in scientific notion”

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Solve what you have ⬆️ ..

Answer: 3.5 × 10³

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6 0
2 years ago
The square of a whole number 'n' lies between 80 and 150. Find all possible values for 'n'.
pychu [463]
The square of a whole number n lies between 80 and 150, so n lies between √80 and √150.

\sqrt{80} \approx 8.9 \\
\sqrt{150} \approx 12.2

n is a whole number and lies between 8.9 and 12.2, so n can be 9, 10, 11, or 12.

The possible values for n are 9, 10, 11, and 12.
5 0
3 years ago
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 8​% will need repairs​
Sladkaya [172]

Answer:

Probability that a car need to be repaired​ once = 20% = 0.20

Probability that a car need to be repaired​ twice = 8% = 0.08

Probability that a car need to be repaired​ three or more = 2% = 0.02

a) If you own two​ cars what is the probability that  neither will need​ repair?

Probability that a car need to be repaired​ once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair=0.7 \times 0.7=0.49

​b) both will need​ repair?

Probability both will need​ repair = 0.3 \times 0.3=0.09

c)at least one car will need​ repair

Neither car will need repair=0.7 \times 0.7=0.49

Probability that at least one car will need​ repair= 1-0.49 = 0.51

6 0
2 years ago
Many do apply pls helpn
Ugo [173]

Answer:

a and b

Step-by-step explanation:

i think b i know a for sho

4 0
3 years ago
Read 2 more answers
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