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kupik [55]
3 years ago
8

A code on a student ID card begins with 3 letters and ends with 5 digits. How many different ID codes are possible if…the letter

s and digits cannot be repeated?
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer:

The total number of combinations is 2,358,720,000

Step-by-step explanation:

For the letter part of the ID we have 3 letters out of a space of 26 possible letters (a-z), and they can't repeat. For the number part we want to group 5 numbers out of 10 possible algarisms (0-9).So we can make an arrangement for the letters and one for the numbers and multiply them. The arrangment can be done using the following formula:

A(n,k) = (n!)/(n-k)!

Where n is the total number of possibilities and k is the size of the group.

For the letters:

A(26,3) = (26!)/(26-3)! = (26!)/(23!) = (26*25*24*23!)/(23!) = 26*25*24 = 15600

For the numbers:

A(10,5) = (10!)/(10 - 5)! = 10!/5! = (10*9*8*7*6*5!)/(5!) = 10*9*8*7*6*5 = 151200

The total number of combinations is the product of both, so:

combinations = 15600*151200 = 2,358,720,000

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velikii [3]

2√2

= 2√2

B)

√3(√2+380√2-80)

= -80√3+381√6


I hope that's help and sorry for the late answer !

5 0
3 years ago
In a G.P the 3rd term is 4 times the 1st term and the sum of the 2nd term and the 4th term is 30.find the common ratio,find the
STALIN [3.7K]

Answer:

the common ratio is either 2 or -2.

the sum of the first 7 terms is then either 765 or 255

Step-by-step explanation:

a geometric sequence or series of progression (these are the most common names for the same thing) means that every new term of the sequence is created by multiplying the previous term by a constant factor which is called the common ratio.

so,

a1

a2 = a1×f

a3 = a2×f = a1×f²

a4 = a3×f = a1×f³

the problem description here tells us

a3 = 4×a1

and from above we know a3 = a1×f².

so, f² = 4

and therefore the common ratio = f = 2 or -2 (we need to keep that in mind).

again, the problem description tells us

a2 + a4 = 30

a1×f + a1×f³ = 30

for f = 2

a1×2 + a1×2³ = 30

2a1 + 8a1 = 30

10a1 = 30

a1 = 3

for f = -2

a1×-2 + a1×(-2)³ = 30

-10a1 = 30

a1 = -3

the sum of the first n terms of a geometric sequence is

sn = a1×(1 - f^(n+1))/(1-f) for f <>1

so, for f = 2

s7 = 3×(1 - 2⁸)/(1-2) = 3×-255/-1 = 3×255 = 765

for f = -2

s7 = -3×(1 - (-2)⁸)/(1 - -2) = -3×(1-256)/3 = -3×-255/3 =

= -1×-255 = 255

4 0
3 years ago
What is the answer to 3(5)​
zmey [24]

Answer: 15

Step-by-step explanation:

3x5=15

4 0
3 years ago
Read 2 more answers
You randomly choose one of the tiles. Without replacing the first tile. What is the event of the compound event? Write your answ
Luden [163]

Answer:

87777777777777777777777777

Step-by-step explanation:

7 0
4 years ago
B -5 ≥ -45 answer and steps
Natalka [10]

Answer:

-50

Step-by-step explanation:

b-5 \geq -45

b-5 = -45 ( collect like terms)

b = -45 + -5

b = -45 -5  b = -50

8 0
2 years ago
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