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alexandr402 [8]
3 years ago
14

If a and b are any two real numbers, than how do you calculate the difference between a-b

Mathematics
1 answer:
Stells [14]3 years ago
4 0
When you're are asking if a and b are any two real numbers then in order to find the difference between the two numbers, you would have to subtract a by b and that would be your difference.
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Diagram/ algebra please help asap needs to be done now
Firlakuza [10]

Answer: 20\ cm

Step-by-step explanation:

For this exercise you need to remember that a Square is defined as a Quadrilateral whose sides are equal in lenght and all its interios angles measure 90 degrees.

Based on that definition, and observing the squarE given in the picture attached, you can write the following equation:

6x-1=4x+6

Then, you need to solve for the variable "x" in order to find its value. You get that this is:

6x-4x-1=6\\\\2x-1=6\\\\2x=6+1\\\\2x=7\\\\x=\frac{7}{2}\\\\x=3.5

Now, knowing the value of "x" you can susbstitute it into any expression that represents the side of the square, and then you must evaluate in order to find the lenght of the side.

You get:

(6x-1)\ cm=(6(3.5)-1)\ cm=(21-1)\ cm=20\ cm

7 0
3 years ago
What are like terms?
Tanya [424]
Like terms are when you have 2 of the same coefficent disregarding the amount of numbers. you can add or subtract them to simplify in other words.
4 0
4 years ago
You roll a number cube. Find the probability and write your answer in the simplest form. P(4)= ---------------------------------
alina1380 [7]

Answer:

P(4) = \frac{1}{6}

P(\text{not a 2}) = \frac{5}{6}

P(\text{3 or 5}) = \frac{1}{3}

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Number cube:

A number cube is a dice, which has six sides, numbered 1 to 6.

P(4)

One the sides is a 4, thus:

P(4) = \frac{1}{6}

P(not a 2)

Of the 6 sides, one is a 2, and the other 5 are not 2. So

P(\text{not a 2}) = \frac{5}{6}

P(3 or 5)

One sides is 3, other is 5, 1 + 1 = 2. So

P(\text{3 or 5}) = \frac{2}{6} = \frac{1}{3}

8 0
4 years ago
Find the area of the shaded region f(x)= x^3+x^2-6x and g(x)=6x. The bounds are [-4,0].
pshichka [43]
If you look at the graph below, the "ceiling" function, is f(x), on that interval of [-4,0], whilst the "floor" function, is g(x)

so, taking that into account, then \bf \begin{cases}
f(x)=x^3+x^2-6x\\\\
g(x)=6x
\end{cases}\qquad \displaystyle \int\limits_{-4}^{0}\ 
\begin{array}{llll}
[ceiling]&-&[floor]\\
f(x)&&g(x)
\end{array}
\\\\\\
thus
\\\\\\
\displaystyle \int\limits_{-4}^{0}\ [[x^3+x^2-6x]-[6x]]dx\implies 
\displaystyle \int\limits_{-4}^{0}\ x^3+x^2-12x
\\\\\\
\left. \cfrac{x^4}{4}+\cfrac{x^3}{3}-6x^2  \right]_{0}^{-4}

4 0
3 years ago
Twenty seven exceeds one twelfth of a number by 13. what is the number
ludmilkaskok [199]
ANSWER:
168

EXPLANATION:
27 - 13 = 14
14 is one twelfth of the number
so 14 x 12 = 168
5 0
3 years ago
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