Compare the ratio of the longest side being 14 1/2 to shortest side 1 1/4 and turn it into a simplified fraction

1 answer:

4 0

(14 1/2)/(1 1/4) change both to improper fractions

(29/2)/(5/4) invert second function (or the denominator fraction) and multiply.

(29/2)*(4/5) multiply...

58/5 change improper fraction back to mixed fraction

11 3/5 or a decimal 11.6

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The equation of a line perpendicular to y = 3 and passes through the point (24, -56).

Lera25 [3.4K]

Answer:

x = 24

Step-by-step explanation:

The given line y = 3 is a horizontal line with slope zero (0).

We wish to find the equation of a line that is perpendicular to y = 3. Such a line would be a vertical one. Vertical lines do not have slopes defined (due to division by zero).

Thus the general form of the equation of this new line is x = c.

This new line passes through (24, -56). Thus, x must be 24: x = 24

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1. Expresa cada función cuadrática f en la forma f(x)-yo = p(x – xo) x ϵ R, donde xo , yo , p ϵ R son elegidos apropiadamente. I

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Answer:

Step-by-step explanation:

1. Express each quadratic function f in the form f (x) -yo = p (x - xo) x ϵ R, where xo, i, p ϵ R are appropriately chosen. Indicate the coordinates

of the vertex of the parabola, the minimum or maximum of the function f, especially R. Draw the graph of f.

a) f (x) = 2x2 + 3x -5, ϵ R,

b) f (x) = -3x2 + 7x +9, ϵ R,

c) f (x) = - x +1, ϵ R,

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2 years ago

f the dean wanted to estimate the proportion of all students receiving financial aid to within 3% with 99% reliability, how many

Oksanka [162]

Answer:

n=1849

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: