Answer:
(sin x)^2*(sec x) is positive in QII
Step-by-step explanation:
(sin x)^2 is always 0 or positive. Here x lies in QII.
sec x is positive when the adjacent side is positive and negative when the adjacent side is negative. In QII the adjacent side is positive.
In summary, (sin x)^2*(sec x) is positive in QII
Answer:
see below
Step-by-step explanation:
16+20/t
Let t=4
16 + 20/4
First we divide
16 + 5
Then we add
21
√m/3 = 4
To remove the radical sign, square both sides.
(√m/3)² = 4²
m/3 = 16
To remove the denominator of 3, multiply both sides by 3.
3 (m/3) = 3(16)
m = 48
To check: Substitute m by its value.
√m/3 = 4
√48/3 = 4
√16 = 4
4 = 4
Answer:
20 feet
Step-by-step explanation:
66/3.3
it's twenty i dont know what else to say
First, distribute the 3 to the parentheses.
2x + 16 = 3x - 27
Add 27 to the left.
2x + 43 = 3x
Subtract 2x to the right.
43 = x
