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4 years ago

WILL MARK BRAINLIEST

Mathematics

1 answer:

Dennis_Churaev [7]4 years ago

6 0

Find the area of the circle

A of circle = πr²

radius = diameter/2 = 48/2 = 24

Area = (3.14)(24)²
Area = 1808.64 in²

Hope this helps :)

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What is the momentum of a 110 kg professional fullback running across the line at 9.2 m/s

Naya [18.7K]

Answer:

$p = 1012\ kgm/s$

Step-by-step explanation:

In physics the linear momentum p of an object is defined as the product of its mass by its velocity.

$p = mv$

Where m is mass and v is velocity

In this case the professional fullback has a mass $m = 110\ kg$ and a speed $v = 9.2\ m / s$

Then the momentum is:

$p = 110*9.2$

$p = 1012\ kgm/s$

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3 years ago

Eye how many 3’s are in this image

REY [17]

There is no image, what does that mean?

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4 years ago

Read 2 more answers

Could someone help me with this?

hodyreva [135]

Step-by-step explanation:

Identity the variable:

Initial Velocity is 35.

Initial Height is 204

Final Height is 0.

What looking for the time.

So we have

$0 = - 16 {t}^{2} + (35)t + 204$

Use Quadratic Formula,

$- b± \frac{ \sqrt{b {}^{2} - 4ac} }{2a}$

A is -16, B is 35 , C is 204.

So we have

$- 35± \frac{ \sqrt{ {35}^{2} - 4( - 16)(204) } }{ - 32}$

$- 35± \frac{ \sqrt{1225 + 2240} }{ - 32}$

$- 35± \frac{ \sqrt{3465} }{ - 32}$

${35} ± \frac{ \sqrt{3465} }{ - 32}$

The positve solution is

$4.83$

So the answer is 4.83 seconds

5 0

2 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

3 years ago

What is the length of a rectangle with width 14in. and area 91in.²?

sleet_krkn [62]

Answer:

91 divided by 14 = 6.5 is the length

Step-by-step explanation:

Whenever given an area and 1 given length always divide the area by the length to find the missing length.

7 0

3 years ago