Answer:
solution is ![\boxed{x=-1,x=-11}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D-1%2Cx%3D-11%7D)
Step-by-step explanation:
f(x)=2|x+6|-4
either x+6 is positive and then |x+6|=x+6
or it is negative and |x+6| = -(x+6)=-x-6
case 1: x>=-6
f(x)= 2x+12-4=2x+8
f(x)=6 <=> 2x+8=6 <=> 2x = 6-8=-2 <=> x = -1
case 2: x<=-6
f(x)=-2x-12-4=-2x-16
f(x)=6 <=> -2x-16=6 <=> 2x=-16-6 = -22 <=> x = -11
so to recap, the solutions are x=-1 and x=-11
Answer:
13
c+24
f
+
8
h
+
17
m
+
4
s
Step-by-step explanation:
-(x-3)=-x+3
First, distribute -1 to x and -3.
-x+3=-x+3
As you can see, both sides are equal. You can continue to simplify:
Add x to both sides to get rid of the variable.
3=3 or infinitely many solutions because x can equal any number and still be equal to the other side.
I hope this helps :)