Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
12
Step-by-step explanation:
-12 = -3/4x + 3
-9 = -3/4x
-9 = (-3/4) times x
-9 = (-3/4) times 12
hope this helps! :)
Answer:
-6r+6
Step-by-step explanation:
Given data
We are given the expression
8-(6r+2)
let us expand it by opening the bracket
=8-6r-2
collect like terms
=8-2-6r
=6-6r
rearrange
=-6r+6
Hence option A is correct
Answer:
it depends on the choices
Step-by-step explanation:
Answer:
zero property
Step-by-step explanation:
if it equals zero its zero property
