Answer:
2 of the 1/3 Bananas and 5 of the 1/4 strawberries
Step-by-step explanation:
two of the 1/3 bananas can complete the pound of grapes and one of the 1/4 of strawberries can complete the pound of apples so then u got 4 more of 1/4 and u got three pounds exact
Answer:
![\frac{180}{147}](https://tex.z-dn.net/?f=%5Cfrac%7B180%7D%7B147%7D)
Step-by-step explanation:
- Simplify
![(\frac{3}{-7} - \frac{11}{21} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B3%7D%7B-7%7D%20-%20%5Cfrac%7B11%7D%7B21%7D%20%29)
![=> \frac{(-3 \times 3) - 11}{21}](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B%28-3%20%5Ctimes%203%29%20-%2011%7D%7B21%7D)
![=> \frac{-9 - 11}{21}](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B-9%20-%2011%7D%7B21%7D)
![=> \frac{-20}{21}](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B-20%7D%7B21%7D)
- Find the additive inverse of
by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of
.
![=> x + \frac{-20}{21} = 0](https://tex.z-dn.net/?f=%3D%3E%20x%20%2B%20%5Cfrac%7B-20%7D%7B21%7D%20%3D%200)
![=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}](https://tex.z-dn.net/?f=%3D%3E%20x%20%3D%200%20-%20%28-%5Cfrac%7B20%7D%7B21%7D%29%20%3D%20%5Cfrac%7B20%7D%7B21%7D)
- Simplify
![(\frac{9}{5} \div \frac{7}{5} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B9%7D%7B5%7D%20%5Cdiv%20%5Cfrac%7B7%7D%7B5%7D%20%29)
![=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B9%7D%7B5%7D%20%5Ctimes%20%5Cfrac%7B1%7D%7B%5Cfrac%7B7%7D%7B5%7D%20%7D)
![=> \frac{9}{5} \times \frac{5}{7}](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B9%7D%7B5%7D%20%5Ctimes%20%5Cfrac%7B5%7D%7B7%7D)
![=> \frac{9}{7}](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B9%7D%7B7%7D)
- Now, find the product of
& ![\frac{20}{21}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B21%7D)
![=> \frac{9}{7} \times \frac{20}{21}](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B9%7D%7B7%7D%20%5Ctimes%20%5Cfrac%7B20%7D%7B21%7D)
![=> \frac{180}{147}](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B180%7D%7B147%7D)
Given:
![|x-4(72)|=2](https://tex.z-dn.net/?f=%7Cx-4%2872%29%7C%3D2)
To find:
The highest and lowest scores Sam could have made in the tournament.
Solution:
We have,
![|x-4(72)|=2](https://tex.z-dn.net/?f=%7Cx-4%2872%29%7C%3D2)
![|x-288|=2](https://tex.z-dn.net/?f=%7Cx-288%7C%3D2)
It can be written as
![x-288=\pm 2](https://tex.z-dn.net/?f=x-288%3D%5Cpm%202)
Add 288 on both sides.
![x=288\pm 2](https://tex.z-dn.net/?f=x%3D288%5Cpm%202)
and ![x=288+2](https://tex.z-dn.net/?f=x%3D288%2B2)
and ![x=290](https://tex.z-dn.net/?f=x%3D290)
Therefore, the highest and lowest scores Sam could have made in the tournament are 290 and 286 respectively.
A) True is the answer you are looking for.