5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Answer:
S = 60
Step-by-step explanation:
240 divided by 4 is equal to 60
Cross multiply to get 8k+24=56 then solve for k so subtract 24 from each side to get 8k=32 so k=4
Answer:
Hey there!
y=3/4x shows that the y-value is always 3/4 of the x-value.
Thus, if x is 4, y is 3. It always fits the 4:3 ratio.
The ordered pairs that satisfy this equation are: 28:21 and 16:12
Let me know if this helps :)
Answer:
9 times older.
Step-by-step explanation: Mark brainliest if this helps.
