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11111nata11111 [884]
2 years ago
10

Hey does anyone know how to do this? My study guide notes last question( really need some help )

Mathematics
1 answer:
omeli [17]2 years ago
6 0

Answer:

8. 295.2 10.

Step-by-step explanation:

4.8 x 15 x 4.1 = 295.2

4.8 is the height. 15 is the Base. 4.1 is the length

Well, for Volume  of a rectangle is like this

V = b x h x l

b = Base

h =  height

l = length

The formula shows you for SA = 2pi/r^2 + 2pi/rh

I kinda forgot how to solve SA but you might need to look it up.

I have attach a screenshot to help you with figuring out to solve 3D shapes.

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Joe's annual income has been increasing in the same dollar amount. The first year his income was $15,200, and the 4th year his i
lidiya [134]

Answer:

Therefore 6th year his income was $19,700.

Step-by-step explanation:

Given, Joe's annual income has been increasing in some dollar amount . The first year his income was $15,200 and 4th  year his income was $17,900.

A=$17900, P= $15,200 and n = 3 year

A= P(1+\frac{r}{100} )^n

\Leftrightarrow 17900=15200(1+\frac{r}{100})^3

\Leftrightarrow (1+\frac{r}{100})^3=\frac{17900}{15200}

\Leftrightarrow (1+\frac{r}{100})=(\frac{17900}{15200})^{\frac{1}{3} }

\Leftrightarrow \frac{r}{100}=(\frac{17900}{15200})^{\frac{1}{3} }-1

\Leftrightarrow r=5.60

Let  t^{th} year Joe's income was $19,700.

\therefore 19700=15,200(1+\frac{5.60}{100} )^{t-1}

\Leftrightarrow 1.296= (1+0.056)^{t-1}

\Leftrightarrow 1.296= (1.056)^{t-1}

\Leftrightarrow  log(1.296)= (t-1)log(1.056)

\Leftrightarrow  \frac{log(1.296)}{log(1.056)}= (t-1)

\Leftrightarrow t-1= 4.75

\Leftrightarrow t= 4.75+1

\Leftrightarrow t = 5.75 ≈6

Therefore 6th year his income was $19,700.

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