Okay so this friend has a 8, 9, 10 as her options that she pays at.
8: 2,6 9: 6,3 10: 5,5
6,2 3,6 5,5
4,4
4,4
These are the possibilities of rolling these numbers. = 4 possibilities
4/11 (11 because that is the number of possibilities you get for two dice)
that leaves 7/11 possibilities of rolling and not paying!
36% lands on a spot that she pays at and about 64% possibilities of not paying.
Hope this helped!
:)
Answer:
2,21 * 10^20
Step-by-step explanation:
Answer: Required mean would be 15.
Step-by-step explanation:
Since we have given that
Number of girls G= 75
Number of boys B= 100
Probability that girls smoke = P₂ = 0.20
Probability that girls don't smoke = P'₂=1-0.20=0.80
Probability that boys smoke = P₁ = 0.30
Probability that boys don't smoke = P'₁=1-0.30=0.70
We need to find the mean of the sampling distribution of the difference in the sample proportion of girl smokers and boys smokers.
So, it becomes,
![E[P_1-P_2]=E[P_1]-E[P_2]\\\\=B\times P_1-G\times P_2\\\\=100\times 0.30-75\times 0.20\\\\=30-15\\\\=15](https://tex.z-dn.net/?f=E%5BP_1-P_2%5D%3DE%5BP_1%5D-E%5BP_2%5D%5C%5C%5C%5C%3DB%5Ctimes%20P_1-G%5Ctimes%20P_2%5C%5C%5C%5C%3D100%5Ctimes%200.30-75%5Ctimes%200.20%5C%5C%5C%5C%3D30-15%5C%5C%5C%5C%3D15)
Hence, required mean would be 15.
Pairs of numbers between 1 and 6 that add up to 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1
Pairs of numbers between 1 and 6 that add up to 8: 2+6, 3+5, 4+4, 5+3, 6+2
Pairs of numbers between 1 and 6 that add up to 9: 3+6, 4+5, 5+4, 6+3
6 for 7, 5 for 8, 4 for 9. 15 in all
Answer:
B
Step-by-step explanation:
180-72 = 108
26+46=72
108+72=180
