The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
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Answer: Xylem carries water from the roots to the leaves.
Explanation:
The above option is a missing option to your question and the correct one.
The Xylem is a kind of vascular tissue that plants have which helps in the transportation of water. It gets water from the roots and transports it to the leaves. It also transports dissolved minerals in the water to those leaves as well.
Phloem tissue transports food from the leaves where it is made to the roots.
Answer:
A.) 9 to 11
Explanation:
I believe that asking as many questions as possible is very useful especially during a job interview. This is so because it allows you a wide range of questions to chose from and to create in which can cover concerns about the general job description of the job in which you are further undergoing. Not only that but it even enables you to gain additional background about past experiences about the job as well as to list out any concerns that can possibly cause hazards or other dangers. To generalize, you get a very detailed concept of the job description and the environment, along with many of the employees with a long range of questions to chose from.
According to Hooke's law, a 30-N force stretches a spring by 0.73 m if the spring constant k is such that
30 N = k (0.73 m)
k = (30 N) / (0.73 m)
k ≈ 4.1 N/m
