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marshall27 [118]

3 years ago

5

PSYCHOLOGY EXAM PLS HELP!!! WILL MARK BRAINLIEST IF U ARE CORRECT Which of the following is the best explanation of the differen

ce between prejudice and discrimination? A. Prejudice is an attitude, and discrimination is an behavior. B. Prejudice is a behavior, and discrimination is an attitude. C. Prejudice is necessary in order for discrimination to exist. D. Discrimination is necessary in order for prejudice to exist.

2 answers:

choli [55]3 years ago

8 0

Answer:

prejudice is an attitude and discrimination is a behavior

Explanation:

"Prejudice has to do with the inflexible and irrational attitudes and opinions held by members of one group about another, while discrimination refers to behaviors directed against another group."

krek1111 [17]3 years ago

4 0

Answer:

A. Prejudice is an attitude, and discrimination is an behavior.

Explanation:

got it right on edge

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Answer:

Explanation:

What is the radius or diameter? I can't help you without that.

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How to watch Sentry Tournament of Champions, Round 1: Tee times, live leaderboard, TV times

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A bakery offers a sale price of $3. 50 for 4 muffins. What is the price per dozen.

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2 years ago

company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul

lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

<em>The proportion of Good TV set is 0.67</em>
<em>The number of ways of selecting 5 from 6 TV sets is 6</em>
<em>The number of ways of selecting 4 from 6 TV sets is 15</em>

<em />

Given

$n = 6$

Sample Space = Good, Good, Defective, Defective, Good, Good

<u>(a) Proportion that are good</u>

From the sample space, we have:

$Good = 4$

So, the proportion (p) that are good are:

$p = \frac{Good}{n}$

$p = \frac{4}{6}$

$p = 0.67$

<u>(b) Ways to select 5 samples (without replacement)</u>

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 5$

So, we have:

$^6C_5 = \frac{6!}{(6 - 5)!5!}$

$^6C_5 = \frac{6!}{1!5!}$

$^6C_5 = \frac{6 \times 5!}{1 \times 5!}$

$^6C_5 = \frac{6}{1}$

$^6C_5 = 6$

Hence, there are 6 ways

<u>(c) All possible sample space of 4</u>

First, we calculate the number of ways to select 4.

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 4$

So, we have:

$^6C_4 = \frac{6!}{(6 - 4)!4!}$

$^6C_4 = \frac{6!}{2!4!}$

$^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}$

$^6C_4 = \frac{30}{2}$

$^6C_4 = 15$

So, the table is as follows:

$\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]$

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

$p = \frac{Good}{n}$

<u>(d) The sampling distribution</u>

In (a), we have:

$p = 0.67$ --- proportion of Good TV

The sampling error is calculated as follows:

$SE_n = |p - p_n|$

So, we have:

$\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]$

Read more about sampling distributions at:

brainly.com/question/10554762

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3 years ago

If 2a+3b=12 and 3b-4=2, then what is the value of a?

IceJOKER [234]

If 3b - 4 = 2, then 3b = 6, or b = 2. If b = 2, then 2a + 3(2) = 12 2a + 6 = 12 2a = 6 and then a = 3.

7 0

2 years ago

Read 2 more answers