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lisabon 2012 [21]
3 years ago
12

Find the equation of the line parallel to the line graphed that passes through the point (1,1).

Mathematics
2 answers:
pickupchik [31]3 years ago
5 0

Answer:

i think it is a.y=2x + 1 2

Step-by-step explanation:


kakasveta [241]3 years ago
3 0
Find the equation of the line parallel to the line graphed that passes through the point (1,1).
A)y = 2x + 1 2
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What is the value of the expression 5(X+3) when X=-3?
SIZIF [17.4K]

Answer:

0

Step-by-step explanation:

5(x+3) replace x with -3

5(-3+3)

5(0)

0

4 0
3 years ago
HOW DO I SOLVE THIS??<br> What would the answer be??<br> THANKS!
Arisa [49]
Convert 300% into decimals. So move the decimal point 2 times to the left and you get 3.00 and multiply it by 5 and square it because area of square is s^2
7 0
4 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0
3 years ago
PLEASE HELP LOVELIES?? xxx
Lelechka [254]
The data set has no association.
4 0
4 years ago
An object that weighs 1 pound on earth weighs only 0.17 pounds on the moon. Zach's dog weighs 17 1/2 pounds on earth. How much m
PtichkaEL [24]
 its actually .16 not .17
 284.192
3 0
3 years ago
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