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Katarina [22]
4 years ago
14

A bag contains 7 red marbles, 5 yellow marbles, 6 blue marbles, 4 green marbles, and 3 orange marbles. What is the probability o

f randomly selecting a yellow marble out of the bag?
Mathematics
2 answers:
Trava [24]4 years ago
8 0

Answer:

1/5

Step-by-step explanation:

baherus [9]4 years ago
6 0

The probability of randomly selecting a yellow marble out of the bag is \frac{1}{5}

Step-by-step explanation:

A bag contains:

  • 7 red marbles
  • 5 yellow marbles
  • 6 blue marbles
  • 4 green marbles
  • 3 orange marbles

We need to find the probability of randomly selecting a yellow marble out of the bag

Probability is the ratio of number of favorable outcomes to the total number of possible outcomes P(A) = \frac{n(A)}{n(outcoms)}

∵ A bag contains 7 red marbles, 5 yellow marbles, 6 blue

   marbles, 4 green marbles, and 3 orange marbles

- Add all the color to find the number of total marbles

∴ n(all) = 7 + 5 + 6 + 4 + 3 = 25

∵ There are 5 yellow marbles

∵ P(yellow) = \frac{n(yellow)}{n(all)}

∴ P(yellow) = \frac{5}{25}

- Divide up and down by 5 to simplify the fraction

∴ P(yellow) = \frac{1}{5}

The probability of randomly selecting a yellow marble out of the bag is \frac{1}{5}

Learn more:

You can learn more about the probability in brainly.com/question/9178881

#LearnwithBrainly

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8 0
3 years ago
A manufacturer of processing chips knows that 2\%2%2, percent of its chips are defective in some way. Suppose an inspector rando
kipiarov [429]

The data in the question seems a bit erroneous. I am writing the correct question below:

A manufacturer of processing chips knows that 2%, percent of its chips are defective in some way. Suppose an inspector randomly selects 4 chips for an inspection. Assuming the chips are independent, what is the probability that at least one of the selected chips is defective? Lets break this problem up into smaller pieces to understand the strategy behind solving it.

Answer:

The probability that at least one of the selected chips is defective is 0.0776.

Step-by-step explanation:

The question states that the probability of defective chips is 2% i.e. 0.02. Let p denote the probability of selecting a defective chip so, p = 0.02

An inspector selects 4 chips, which means n=4 and we need to compute the probability that at least one of the selected chips is defective. Let X be the number of defective chips selected. We need to compute P(X≥1) which means either 1, 2, 3 or 4 chips can be defective.

We will use the binomial distribution formula to solve this problem. The formula is:

<u>P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ</u>

where n = total no. of trials

          p = probability of success

          x = no. of successful trials

          q = probability of failure = 1-p

we have n=4, p=0.02 and q=1-0.02=0.98.

We need to compute P(X≥1) which is equal to:

P(X≥1) = P(X=1) + P(X=2) + P(X=3) + P(X=4)

A shorter method to do this is to use the total probability theorem:

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ (0.02)⁰(0.98)⁴⁻⁰

          = 1 - (0.98)⁴

          = 1 - 0.9224

P(X≥1) = 0.0776

4 0
4 years ago
What is 10.5% commission of $85,000
VikaD [51]
<span>What is 10.5% commission of $85,000

85,000 x 0.105 = 8,925

answer
$8,925 is </span>10.5% commission of $85,000
8 0
3 years ago
Using pemdas please
Bond [772]

 4^{3}+2(8)=80

Solution:

Given expression:

 4^{3}+2(8)

<u>Expansion of PEDMAS: </u>

Parenthesis, Exponents, Division, Multiplication, Addition, Subtraction.

To solve the given expression using pedmas rule.

First solve the expression with parenthesis.

 4^{3}+2(8)=4^{3}+16

Next do the exponents.

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Finally do the addition.

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Hence the answer is 80.

6 0
3 years ago
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Between what two consecutive integers is 17?
Marina CMI [18]

Answer:

No solution

Step-by-step explanation:

17 is an integer that is in between the integers of 16 and 18

16 and 18 are not consecutive integers.

No solution

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3 years ago
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