Well technically the check will not go through because she does not have a balance greater than or equal to $55, but if you need an answer it would be $47-$55= $-8.

8 0

3 years ago

Read 2 more answers

Please help me thank youuu

FrozenT [24]

Answer:

Step-by-step explanation:

The solutions to the equation f(x) = g(x) are the values of x where the function values are equal. These are the x-coordinates of the points where the graphs of y=f(x) and y=g(x) intersect each other.

<h3>Points of intersection</h3>

The points where the graphs cross can be estimated to be ...

(-3.8, 6.5) and (3, -6)

The x-coordinates of these points are the solutions to the equation:

x = -3.8, 3

8 0

2 years ago

Help math question derivative!

atroni [7]

Let $f(x)=\sec^{-1}x$ . Then $\sec f(x)=x$ , and differentiating both sides with respect to $x$ gives

$(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1$
$f'(x)=\dfrac1{\sec f(x)\tan f(x)}$

Now, when $x=\sqrt2$ , you get

$(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}$

You have $\sec^{-1}\sqrt2=\dfrac\pi4$ , so $\sec\left(\sec^{-1}\sqrt2\right)=\sqrt2$ and $\tan\left(\sec^{-1}\sqrt2\right)=1$ . So $(\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}$

5 0

3 years ago

Which of the following are like terms to the term 2x (which more than one apply?

GuDViN [60]

-2x and 4x
and x2 so tats it

6 0

3 years ago