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4 years ago

Which math expression???? 7th grade

Mathematics

2 answers:

DiKsa [7]4 years ago

8 0

I think it's A because of PEMDAS so you multiply 8 by n-3

Digiron [165]4 years ago

7 0

If you do PEMDAS on that problem you will get answer A

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Using the fractions 2/3 and 3/4 describe how to give two fractions common denominators

Contact [7]

One way is to find the prime factorization for the denominators which are 3 and 4. The prime factorization of 3 would be 1 x 3 and 4 would be 2 x 2. Since we only use prime numbers to find the prime factorization we would have 2 x 2 x 3 = 12 which give us the the least common denominator for 2/3 and 3/4. Final answer is 12.

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3 years ago

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The animal shelter has both male and female Labrador Retrievers in yellow, brown, or black. There is an equal number of each kin

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school is asking us to find the probability of dogs breeding I’m sorry I don’t understand

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3 years ago

1. Solve 49 square <br><br><br>2. Solve 64 square

torisob [31]

Answer:

1. 7

2. 8

Step-by-step explanation:

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3 years ago

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beach hotel in north lake tahoe is offering 2 weekend specials one includes 1 2 night stay with 3 meals and costs $195 the other

adell [148]

Answer:

$94.50

Step-by-step explanation:

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so that will be $94.50 for a single meal

6 0

4 years ago

13. Write

Bingel [31]

First off, we factor out the expression:

$\displaystyle \large{y = 2 {x}^{2} - 12x + 16} \\ \displaystyle \large{y = 2 ( {x}^{2} - 6x + 8) }$

In the bracket, separate 8 out of the expression.

$\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 8)] }\\ \displaystyle \large{y = 2[ ( {x}^{2} - 6x) + 8]}$

In x^2-6x, find the third term that can make up or convert it to a perfect square form. The third term is 9 because:

$\displaystyle \large{ {(x - 3)}^{2} = {x}^{2} - 6x + 9}$

So we add +9 in x^2-6x.

$\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 9) + 8]}$

Convert the expression in the small bracket to perfect square.

$\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8]}$

Since we add +9 in the small bracket, we have to subtract 8 with 9 as well.

$\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8 - 9]} \\ \displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]}$

Then we distribute 2 in.

$\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\$

$\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\ \displaystyle \large{y = [2 \times {(x - 3)}^{2} ]+[ 2 \times ( - 1)] } \\ \displaystyle \large{y = 2 {(x - 3)}^{2} - 2 }$

Remember that negative multiply positive = negative.

Hence the vertex form is y = 2(x-3)^2-2 or first choice.

4 0

3 years ago