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2 years ago

PLEASE SOMEONE HELP ME WITH #2

Mathematics

1 answer:

Bogdan [553]2 years ago

4 0

equation : c=£1.25 for example to find out 3 cans : 3c= £1.25x3

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(12 - 8)3 – 24 x 2 Plz help me

yawa3891 [41]

La réponse est -36
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2 years ago

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marta [7]

Answer:

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Step-by-step explanation:

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2 years ago

Please help i don't even where to start solve for x

aliina [53]

The radius is 10, so the diameter is 20. This means the parts of the diameter (the chord through the center P) to the left and right of the vertical chord have lengths 16 and 4, respectively.

Because the horizontal chord is a diameter, the vertical chord is cut in half, so its parts above and below the diameter both have length x.

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3 years ago

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abruzzese [7]

Answer:

A is the correct answer to the problem!

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2 years ago

Read 2 more answers

An art history professor assigns letter grades on a test according to the following scheme.A: Top 5% of scoresB: Scores below th

adoni [48]

Answer:

Grade B score:

$76 \leq x \leq 89$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73.3

Standard Deviation, σ = 9.7

We are given that the distribution of score on test is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

B: Scores below the top 5% and above the bottom 62%

We have to find the value of x such that the probability is 0.62

$P( X > x) = P( z > \displaystyle\frac{x - 73.3}{9.7})=0.62$

$= 1 -P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.62$

$=P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.38$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 73.3}{9.7} = 0.305\\\\x = 76.26$

We have to find the value of x such that the probability is 0.05

$P(X < 0.95) = \\\\P( X < x) = P( z < \displaystyle\frac{x - 73.3}{9.7})=0.95$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 73.3}{9.7} = 1.645\\\\x = 89.26$

Thus, the numerical value of score to achieve grade B is

$76 \leq x \leq 89$

7 0

3 years ago