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Tju [1.3M]
3 years ago
11

an assembly line worker at Rob's Bicycle factory adds a seat to a bicycle at the rate of 2 seats in 11 minutes. Write a proporti

on relating the number of seats s to the number of minutes m. At this rate, how long will it take to add 16 seats? 19 seats?
Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0
Rate = 2 seats/11 minutes = 2/11  seats/min

Therefore the time required for s seats is
(m \, min) =  \frac{s \, seats}{ \frac{2}{11} \,  \frac{seats}{min} } =  \frac{11s}{2} \, min
That is,
m = (11s)/2 min

When s = 16, obtain
m =  \frac{11(16)}{2} = 88 \, min

When s = 19, obtain
m =  \frac{11(19)}{2} = 104.5 \, min

Answers:
m = \frac{11s}{2}
When s = 16, m = 88 min
When s = 19,  m = 104.5 min


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To test the belief that sons are taller than their​ fathers, a student randomly selects 13 fathers who have adult male children.
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Answer:

1) B. The differences are normally distributed or the sample size is large

C. The  sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀:  \bar x_1 =  \bar x_2

The alternative hypothesis Hₐ: \bar x_1 <  \bar x_2

Test statistic, t = -0.00693

p- value = 0.498

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers  at 0.10 level of significance

Step-by-step explanation:

1) B. The differences are normally distributed or the sample size is large

C. The  sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀:  \bar x_1 =  \bar x_2

The alternative hypothesis Hₐ: \bar x_1 <  \bar x_2

The test statistic for t test is;

t=\dfrac{(\bar{x}_1-\bar{x}_2)}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}

The mean

Height of Father, h₁,  Height of Son h₂

72.4,      77.5

70.6,      74.1

73.1,       75.6

69.9,      71.7

69.4,      70.5

69.4,      69.9

68.1,       68.2

68.9,      68.2

70.5,       69.3

69.4,       67.7

69.5,       67

67.2,       63.7

70.4,       65.5

\bar x_1  = 69.6      

s₁ = 1.58

\bar x_2 = 69.9

s₂ = 3.97

n₁ = 13

n₂ = 13

t=\dfrac{(69.908-69.915)}{\sqrt{\dfrac{3.97^{2}}{13}-\dfrac{1.58^{2} }{13}}}

(We reversed the values in the square root of the denominator therefore, the sign reversal)

t = -0.00693

p- value = 0.498 by graphing calculator function

P-value > α Therefore, we do not reject the null hypothesis

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers  at 0.10 lvel of significance

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