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g100num [7]
3 years ago
6

What is the square root of 18 plus the square root of 2? And is it rational or irrational?​

Mathematics
1 answer:
kicyunya [14]3 years ago
6 0
The answer is (rounded to the nearest tenth) about 5.7 and since neither 18 or 2 have a perfect square, so this is irrational.
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What is the solution to 2x+10y=-14 and x+5y=-7 answer using elimination with steps
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Step-by-step explanation:

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What is the name of a shape with two parallel sides and four right angles
Sonja [21]
A square has two parallel sides and four right angles.
6 0
3 years ago
Read 2 more answers
The diagonal AC is drawn in parallelogram ABCD Which method can NOT be used to prove that AABC is congruent to ACDA?
diamong [38]

Answer:

B SSA

Step-by-step explanation:

Geometric proofs can be used to show that the two triangles are congruent using ASA, SAS and SSS.

However, there is no such thing as SSA in geometry because an angle and two sides can not show congruence of triangles. This is so because the angle is not an included angle.

5 0
3 years ago
Which of the following figures could represent the cross section of a rectangular pyramid? Select all that apply.
Rama09 [41]

Answer:

Options C and E

Step-by-step explanation:

Option A. Circle

We can't get a cross section in the form of a circle.

Option B. Cube

We can't get a cross section in the form of a cube.

Option C. Rectangle

When we slice a rectangular pyramid parallel to the base but not through the vertex, we get a Rectangle.

Option D. Square

We can not get a square by slicing a rectangular pyramid.

Option E. Triangle

By slicing a rectangular pyramid perpendicular to the base and passing through the vertex we can get the cross section in the form of  triangle.

Options C and E will be the answer.

4 0
3 years ago
Need answer to 4 and 5
algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $ g_n  = 2 . 3^{n - 1} $

To find the first term, substitute n = 1.

Therefore, $ g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1  $ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3 $ = 6

$ g_3 =  2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9 $ = 18

$ g_4 = 2 . 3^{4  - 1} = 2 . 3^{3} = 2 . 27 $ = 54

$ g_5 =  2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81 $ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $ t_n = \frac{2}{3}t_{n - 1} $

$ t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1  = \frac{2}{3}6 $ = 4

$ t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3} $

$ t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9} $

$ t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27} $

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0
3 years ago
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