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nexus9112 [7]
3 years ago
7

If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f

or which x = 0? Assume SI units.
Mathematics
1 answer:
poizon [28]3 years ago
3 0

Answer:

The first occurence of t for which x = 0 is t = 0.5.

Step-by-step explanation:

The harmonic motion is described by the following equation.

x(t) = 3\cos{\pi t}

What is the first occurrence of a value of t for which x = 0?

This is t when x(t) = 0. So

x(t) = 3\cos{\pi t}

3\cos{\pi t} = 0

\cos{\pi t} = \frac{0}{3}

\cos{\pi t} = 0

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

\arccos{\cos{\pi t}} = \arccos{0}

\pi t = \frac{\pi}{2}

t = \frac{\pi}{2 \pi}

t = \frac{1}{2}

t = 0.5

The first occurence of t for which x = 0 is t = 0.5.

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To make this easier, let's assign x a value. Let's say 3.

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Now with this, we put x in the answer choice and the answer that gives an area of 229 is correct.

A. A=(3+20)(3+10)+12=(23)(13)+12=299+12=311 <u>Answer A is wrong.</u>

B. A=(3+20)(3+10)-12=(23)(13)-12=299-12=287 <u>Answer B is wrong.</u>

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New answer choices!

A. A=(3+20)(3+11)

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B. A=(3+15)(3+10)+5

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