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LekaFEV [45]
3 years ago
15

Please help..............​

Mathematics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

It will hold the icecream as it melts.

Step-by-step explanation:

Volume of sphere = ⁴/3 × pi × r²

Diameter of sphere = 2 inches

Radius of sphere = 1 in

Vol. = 4/3 × 22/7 × 1²

= 4.19 in³

Volume of cone = pi × r² × h/3

Diameter = 2 in

Radius = 1 in

Depth/height = 5 in

Vol = 22/7 × 1² ×5/3

= 5.24 in³

Conclusion: The volume of the cone is bigger than that of the icecream scoop

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An open metal tank of square base has a volume of 123 m^3
snow_lady [41]

Answer:

  a) h = 123/x^2

  b) S = x^2 +492/x

  c) x ≈ 6.27

  d) S'' = 6; area is a minimum (Y)

  e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

  V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

  123 = x^2·h

  h = 123/x^2

__

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}

__

c) The derivative of the area with respect to x is ...

S'=2x-\dfrac{492}{x^2}

When this is zero, area is at an extreme.

0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583

__

d) The second derivative is ...

S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6

This is positive, so the value of x found represents a minimum of the area function.

__

e) The minimum area is ...

S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78

The minimum area of metal used is about 117.78 m².

3 0
3 years ago
-4 1/2x - 3/7= 1/4<br>find x
DiKsa [7]
- 4(1/2)x - (3/7) = (1/4)
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-(9/2)x = 19/28
x = (19/28) * 2 / 9
x = (19/14) / 9
x = 19 / (14*9)
x = 19 / 126
7 0
3 years ago
Can anyone help me with this?
Alexxandr [17]
-1


The inequality is negative 1
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3 years ago
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Hello,

if p is false then ~p is true

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