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erica [24]
3 years ago
8

Do toy have a triangle with a 3 angles:60 degrees, 60 degrees, 63 degrees

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

no.

Step-by-step explanation:

a triangle can only have 180° in total but

60+60+63

=183°

Therefore a triangle can not have these three angles together.

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Find the area of a regular octagon with an apothem length of 10 and a side length of 6.
Sauron [17]

Answer:

A = 240 units²

Step-by-step explanation:

the area (A) of a regular polygon is

A = \frac{1}{2} pa ( p is the perimeter and a the apothem )

here p = 8 × 6 = 48 ( an octagon has 8 sides ) and a = 10 , then

A = \frac{1}{2} × 48 × 10 = 24 × 10 = 240 units²

8 0
2 years ago
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Solve the equation for x∈Z <br><br>-x² +8x -14 ≥ 0
kenny6666 [7]
ax^2+bx+c=0\\\Delta=b^2-4ac\\if\ \Delta < 0\ then\ no\ solutions\\if\ \Delta=0\ then\ one\ solution:x=\frac{-b}{2a}\\if\ \Delta > 0\ then\ two\ solutions:x=\frac{-b\pm\sqrt\Delta}{2a}\\================================\\\\-x^2+8x-14\geq0\ \ \ \ |multiply\ both\ sides\ by\ (-1)\ \{change\ \geq\ on\ \leq\}\\\\x^2-8x+14\leq0\\\\a=1;\ b=-8;\ c=14\\\\\Delta=(-8)^2-4\cdot1\cdot14=64-56=8 > 0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2

x_1=\frac{-(-8)-2\sqrt2}{2\cdot1}=\frac{8-2\sqrt2}{2}=\frac{8}{2}-\frac{2\sqrt2}{2}=\boxed{4-\sqrt2}\\\\x_2=\frac{-(-8)+2\sqrt2}{2\cdot1}=\frac{8+2\sqrt2}{2}=\frac{8}{2}+\frac{2\sqrt2}{2}=\boxed{4+\sqrt2}\\\\============================

ax^2+bx+c=0\\\\if\ a > 0\ then\ the\ parabola\ o pen\ up\\if\ a < 0\ then\ the\ parabola\ o pen\ down\\========================\\\\a=1 > 0-therefore\ o pen\ up\ (look\ at\ the\ picture)\\\\===============================\\\\Answer:x\in\left


Solutions\ in\ \mathbb{Z}:\\\\\sqrt2\approx1.4\\\\threfore:4-\sqrt2\approx4-1.4=2.6\ and\ 4+\sqrt2\approx4+1.4=5.4\\\\look\ at\ the\ second\ picture:x=3\ or\ x=4\ or\ x=5\ (x\in\{3;\ 4;\ 5\})

6 0
3 years ago
Read 2 more answers
Help me please with this geometry
Tasya [4]
All Triangles are equilateral ( each side = 4)


Area of a Triangle is (B x H)/2. B being the base ( 4) & H the altitude.

WE know that altitude in an equilateral triangle, H = ( side x√3)/2

So H= (4√3)/2 = 2√3

The area of one triangle = (4 x 2√3)/2 = 4√3

And for the 3 triangles the lateral area = (4√3) x 3 = 12√3
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3 years ago
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Stels [109]
A varible represents the number u are looking for. 

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3 0
3 years ago
Please answer this correctly without making mistakes
Monica [59]

Answer:

g=56

Step-by-step explanation:

In similar shapes, corresponding sides are always in the same ratio.

For example,

if the sides in triangle 1 were a and b, and triangle 2 had side lengths c and d, c and a had the same ratios, and b and d had the same ratios

and triangle 1 was similar to triangle 2, the ratio between the sides of the triangles would be

a/c, which is also equal to b/d

What that means is that in this situation, 8/5=g/35.

8/5=g/35

Cross multiply.

(8)*(35)=g*(5)

280=5g

g=56

4 0
3 years ago
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