Vic and Dan are 2, 897m apart.
<h3>How to determine the distance</h3>
It is important to note that the distance between Vic and Dan is the base of CN
Let's say the distance to Dan is x
The distance to Vic is y
Using cosine ratio, we have
cos α = opposite / adjacent
α = 72°
opposite = 553. 3cm
Adjacent = x
cos 72° = 
Cross multiply
× 
= 
m
The distance to Vic is y
Using the cosine ratio, we have
Cross multiply
m
To determine how far apart Vic and Dan, we use = x + y
= 1790. 61 + 1106. 6
= 2, 897. 21m
= 2, 897m
Thus, Vic and Dan are 2, 897m apart.
Learn more about bearing and distance here:
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The last one , because I will now solve it for you and prove therefore.
x²–4x+5=0;
D=(–4)²–4•5=16–20= –4= (2i)².
So:
x1= (4–2i)/2= 2–i
x2= (4+2i)2= 2+i.
This is the whole answer....
Three other u will solve by yourself and have roots which will not be suitable.
<em>Answer</em><em>:</em>
the surface area of the rectangular pyramid below is 300 units2
I don't know how your teacher chooses to solve this problem (or your text) but I do it this way.
Divide 81 by 3. You get 27.
Use 27 as your middle integer and go one odd integer up and down for the other 2.
25, 27, 29
the largest would be 29.
This works because 3 of the middle number equals 81, so the middle number plus a number 2 greater and a number 2 less would still be the same as adding 3 of the same number.
Check by adding the 3 numbers.
25 + 27 + 29 = 81
4 is the slope because the formula for slope is (y2-y1) / (x2-x1) or (8-0) / (3-1) which simplifies to 8/2 = 4
