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2 years ago

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Vic is standing on the ground at a point directly south of the base of the CN Tower and can see the top when looking at an angle

of elevation of 61°. Dan is standing on the ground at a point directly west of the base of the tower and must look up at an angle of elevation of 72° in order to see the top. If the CN Tower is 553.3 m tall,how far apart are Vic and Dan to the nearest meter? Include a well-labeled diagram as part of your solution.

1 answer:

mel-nik [20]2 years ago

7 0

Vic and Dan are 2, 897m apart.

<h3>How to determine the distance</h3>

It is important to note that the distance between Vic and Dan is the base of CN

Let's say the distance to Dan is x

The distance to Vic is y

Using cosine ratio, we have

cos α = opposite / adjacent

α = 72°

opposite = 553. 3cm

Adjacent = x

cos 72° = $\frac{553. 3}{x}$

Cross multiply

$cos 72$ × $x$ = $553. 3$

$0. 3090x= 553. 3$

$x = \frac{553. 3}{0. 3090}$

$x = 1, 790. 61$ m

The distance to Vic is y

Using the cosine ratio, we have

$cos 60 = \frac{553. 3}{y}$

Cross multiply

$0. 5y = 553. 3$

$y = \frac{553. 3}{0. 5}$

$y = 1,106. 6$ m

To determine how far apart Vic and Dan, we use = x + y

= 1790. 61 + 1106. 6

= 2, 897. 21m

= 2, 897m

Thus, Vic and Dan are 2, 897m apart.

Learn more about bearing and distance here:

https://brainly.in/question/47782732

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