Question

Vic is standing on the ground at a point directly south of the base of the CN Tower and can see the top when looking at an angle of elevation of 61°. Dan is standing on the ground at a point directly west of the base of the tower and must look up at an angle of elevation of 72° in order to see the top. If the CN Tower is 553.3 m tall,how far apart are Vic and Dan to the nearest meter? Include a well-labeled diagram as part of your solution.

Answer 1

Vic and Dan are 2, 897m apart.

How to determine the distance

It is important to note that the distance between Vic and Dan is the base of CN

Let's say the distance to Dan is x

The distance to Vic is y

Using cosine ratio, we have

cos α = opposite / adjacent

α = 72°

opposite = 553. 3cm

Adjacent = x

cos  72° = $\frac{553. 3}{x}$

Cross multiply

$cos 72$ × $x$ = $553. 3$

$0. 3090x= 553. 3$

$x = \frac{553. 3}{0. 3090}$

$x = 1, 790. 61$ m

The distance to Vic is y

Using the cosine ratio, we have

$cos 60 = \frac{553. 3}{y}$

Cross multiply

$0. 5y = 553. 3$

$y = \frac{553. 3}{0. 5}$

$y = 1,106. 6$m

To determine how far apart Vic and Dan, we use = x + y

= 1790. 61 + 1106. 6

= 2, 897. 21m

= 2, 897m

Thus, Vic and Dan are 2, 897m apart.

Learn more about bearing and distance here:

https://brainly.in/question/47782732

#SPJ1