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sergij07 [2.7K]
3 years ago
10

Solve for x

ac%7Ba%7D%7Bb%2Bc%7D%20" id="TexFormula1" title=" \frac{a}{x} + \frac{b}{c} = \frac{a}{b+c} " alt=" \frac{a}{x} + \frac{b}{c} = \frac{a}{b+c} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
larisa86 [58]3 years ago
4 0
Easy
make denomenators the same

Step 1
multiply both sidesby (x)(c)(b+c)
(a)(c)(b+c)+(b)(x)(b+c)=(a)(x)(c)

Step 2
distribute
acb+ac²+xb²+bxc=axc

Step 3
minus (acb+ac²) from both sides
xb²+bxc=axc-acb-ac²

Step 4
minus axc from both sides
xb²+bxc-axc=-acb-ac²

Step 5
undistribute x
x(b²+bc-ac)=-acb-ac²

Step 6
divide both sides by (b²+bc-ac)
x= \frac{-acb-ac^2}{b^2+bc-ac} =\frac{acb+ac^2}{ac-b^2-bc}
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Question 6 (1.25 points)
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Test statistic Z= 1.713

The calculated Z- value =  1.7130 < 2.576 at 0.01 level of significance

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There is no difference between the  mean annual salary of all lawyers in a city is  different from $110,000

Step-by-step explanation:

<u><em>Step(i):-</em></u>

A researcher wants to test if the mean annual salary of all lawyers in a city is

different from $110,000

Mean of the Population  μ = $110,000

Sample size 'n' = 53

Mean of the sample x⁻ = $114,000.

standard deviation of the Population = $17,000,

Level of significance = 0.01

Null hypothesis :

There is no difference between the  mean annual salary of all lawyers in a city is  different from $110,000

H₀:  x⁻ =  μ

Alternative Hypothesis :  x⁻ ≠  μ

<u><em>Step(ii)</em></u>:-

Test statistic

                 Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

                 Z = \frac{114000-110000}{\frac{17000}{\sqrt{53} } }

                Z =  1.7130

Tabulated value Z = 2.576 at 0.01 level of significance

The calculated Z- value =  1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the  mean annual salary of all lawyers in a city is  different from $110,000

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3 years ago
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