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Softa [21]
3 years ago
15

There is a math joke that floats around the internet every once in a while that goes something like . . . A mathematician and he

r infinitely many friends decide to stop by their favorite bar. The first mathematician orders 1 beer, the second orders 1/2 a beer, the third orders 1/4 a beer, the fourth orders 1/8 a beer, the fifth orders 1/16 a beer. . . it’s at this point the bartender, knowing a little math herself, interrupts and says "Fine, I’ll just pour you two beers.". How many beers should the bartender pour if the first mathematician orders 6 beers, the second orders 2 beer, the third orders 2/3 a beer, and so on?
Mathematics
1 answer:
salantis [7]3 years ago
6 0

Answer:

  • Three beers.

Step-by-step explanation:

The first mathematician orders 1 beer, the second orders 1/2 a beer, the third orders 1/4 a beer, the fourth orders 1/8 a beer, the fifth orders 1/16 a beer. . .

  • The Sequence is: 1,\frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16} \cdots
  • On observation, the next term is derived through the division of the previous term by 2.
  • 2 is the constant factor
  • Therefore, the bartender says 'Fine, I’ll just pour you two beers.'

Therefore, if the first mathematician orders 6 beers, the second orders 2 beer, the third orders 2/3 a beer, and so on

  • The sequence is 6,2,\frac{2}{3}, \cdots
  • On observation, the next term is derived through the division of the previous term by 3.
  • 3 is the constant factor
  • Therefore, the bartender should pour three beers.

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