17/100, I believe
(the decimal would be 0.17)
The answer is A to the question
Answer:
The space left inside the cyclinder =36π(h - 24)
step-by-step explanation:
Radius of sphere = 6cm
Diameter of cylinder = 12cm
Radius of cylinder = d / 2 = 12 /2 = 6cm
Formula for volume of a sphere = 4/3 πr³
Formula for volume of volume of a cylinder = πr²h
r = radius
h = height
The volume of one sphere = 4/3πr³
Volume of 4 spheres = 4 * 4/3πr³ = 12/3 πr³ = 4πr³
But radius of the sphere = 6cm
Volume of the sphere = 4 * π * 6³
Volume of the sphere = 864π
Let the space left in the cylinder = x
The space left in the cylinder (x) = volume of the cylinder - total volume of the spheres
x = πr²h - 4πr³
Note : both radius = 6cm and we can just substitue it
x = πr² (h - 4r)
x = π*6² (h - 4*6)
x = 36π (h - 24)
The space left inside the cylinder = 36π(h - 24) since we don't know the value of the height of the cylinder.
The range is the output of the function, and there are many ways to find it and write it. Let's find it first by plugging in all the domain values (domain means input) into the function:



We have all of our values. We can either write the range as:
{

}
or, subtract the smallest value from the largest one:

So, there are those ways to write it, there are more, but I think you should stick with the first way because that's how the problem was presented to you. If you have any questions, hmu!