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3 years ago

HELP!!! Picture included :).

Mathematics

1 answer:

jasenka [17]3 years ago

6 0

Answer:

(A'B'): 3 1/2 IN.

(D'E'): 2 1/2 IN.

(R'S'): 4 IN.

Step-by-step explanation:

Just slice the numbers in half

Also i took the test.

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Prove x²+y² = (x+y) (x-y)

gtnhenbr [62]

Answer:

(x+y)(x-y)

x^2 - xy + xy - y^2

x^2 - y^2

7 0

2 years ago

A cylinder has a base radius of 4m and a height of 6m. What is its volume in cubic m, to the nearest tenths place?

Ronch [10]

<h3>Answer:</h3>

301.6 cubic meters

<h3>Step-by-step explanation:</h3>

A cylinder is a shape with straight sides with circular or oval cross-sections. We know that the cylinder in the question must be a circular cylinder due to its radius description.

Volume Formula

A circular cylinder has a volume of $V=\pi r^2h$ . In this equation, V is the volume, r is the radius, and h is the height. The question tells us that r=4m and h=6m. So, we can plug these values into the formula.

Solving for Volume

To solve plug the values into the formula and rewrite the equation.

$V=\pi *4^2*6$

Next, apply the exponents.

$V=\pi *16*6$

Then, multiply the constants.

$V=\pi *96$

Finally, multiply the remaining terms. Remember to use the pi button on the calculator and not an estimation to get a more exact value.

$V=301.6$

Make sure your answer is rounded to the correct digit. This means that the volume must be 301.6 cubic meters.

6 0

2 years ago

Liz wants to buy her favorite musical group’s new CD. The CD costs $15.24, including tax. Liz gives the store clerk a twenty-dol

Mila [183]

$20.00 - $15.24 = $4.76 in change. I'd say review decimal subtraction which you should have learned in fourth or fifth grade. Hope this helps!

3 0

3 years ago

Which function listed below represents a greater rate of change, and what is the slope of the function?

Flauer [41]

Answer:

Step-by-step explanation:

i cant explan for this quasion but i am not understand this quation

8 0

2 years ago

Solve (x + 4)2 – 3(x + 4) – 3 = 0 using substitution. u = Select the solution(s) of the original equation.

bezimeni [28]

Answer:

$\dfrac{-5-\sqrt{21}}{2},\ \dfrac{-5+\sqrt{21}}{2}$

Step-by-step explanation:

For the equation $(x+4)^2-3(x+4)-3=0$ use the substitution $u=x+4.$ Then the equation will take look

$u^2-3u-3=0.$

Solve this quadratic equation:

$D=(-3)^2-4\cdot 1\cdot (-3)=9+12=21,\\ \\u_{1,2}=\dfrac{-(-3)\pm \sqrt{21}}{2}=\dfrac{3\pm\sqrt{21}}{2}.$

Thus,

$x+4=\dfrac{3-\sqrt{21}}{2}\text{ or }x+4=\dfrac{3+\sqrt{21}}{2},\\ \\x_1=\dfrac{3-\sqrt{21}}{2}-4=\dfrac{-5-\sqrt{21}}{2}\text{ or }x_2=\dfrac{3+\sqrt{21}}{2}-4=\dfrac{-5+\sqrt{21}}{2}.$

8 0

3 years ago

Read 2 more answers