Subtract h + 3 from 67 + 1.

A small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company

sukhopar [10]

Answer:

Step-by-step explanation:

Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.

Suppose that one employee is selected at random from a list of the employees

A) Probability that the selected employee has been with the firm less than 5 years = $\frac{50}{250 } \\= 0.20$

B) Probability that the selected employee has been with the firm between 5 and 10 years

= $\frac{75}{250 } \\= 0.30$

C) Probability that the selected employee has been with the firm more than 10 years

= $\frac{125}{250} =0.50$

a) P(A) = 0.2

P(C) = 0.5

P(A or B) = 0.2+0.3 = 0.5

P(A and C) = 0 (since A and C are disjoint)

7 0

3 years ago

How can I solve this? 10+x = 5(1/5x + 2)

pshichka [43]

You use PEMDAS. Start by distributing the terms in the parentheses. The isolate the variables. To do that you subtract x from one side of the equation to the other side. You always do the other operation. If it is adding you subtract, if your multiplying your dividing and the other way around. Then you subtract 10 from each side. This equation has many solution because all the terms cancel out.

5 0

3 years ago

6th grade math help me, please:))

Leokris [45]

Answer:

40 percent

Step-by-step explanation:

(10/25 ) x 100 = (2/5) x100 = (0.4) x 100 = 40% of the roses was given away.

7 0

3 years ago

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