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3 years ago

Which algebraic expression represents "one-third of the number s, plus t"?

Mathematics

2 answers:

Svetllana [295]3 years ago

7 0

Answer:

The answer is A) s/3 + t

Step-by-step explanation:

The "plus t" portion of the equation is fairly straightforward, and is found in every equation apart from C, immediately ruling it out. Lets assume s=6. Then, one third of 6 would be 2. 2s = 12, and 12 is not equal to 2, so B is not the answer. 1/2 + 6 = 6 1/2, and 6 1/2 is not equal to 2, so D is not the answer. 6/3 = 2, which is one third of 6, so A is the answer.

TiliK225 [7]3 years ago

6 0

Answer:

A) s/3 +t

Step-by-step explanation:

To represent 1/3 of a number, we can simply divide this number by 3, meaning if s is the number, 1/3 of s would be s/3. Now to add t all we have to do is + t, making our answer s/3 + t

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A room can be cleaned in 2 hours if rob and Harry work together. Ron could clean it in 3 hours. How long can harry clean it?

tresset_1 [31]

Answer:

6 hours

Step-by-step explanation:

Let the total work be X

Combined speed: X/2

Ron's speed: X/3

Harry's speed: S

X/2 = X/3 + S

S = X/2 - X/3 = (3X - 2X)/6 = X/6

Harry's speed is X/6, so he'll take 6 hours

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3 years ago

A rectangular plot of land is to be enclosed by a fence. One side is along a river, and does not need to be enclosed. If the tot

Bad White [126]

Answer:

Width 150 meters.

Length = 350 meters.

Step-by-step explanation:

Let us assume the width of the fence = k meters

So, both sides = k + k = 2k meters

Also, the TOTAL fencing length = 600 m

So, the one side length of the fence = (600 - 2 k) meters

AREA = LENGTH x WIDTH

⇒ A(k) = (600 - 2k) (k)

or, A = -2k² + 600 k

The above equation is of the form: ax² +bx + C

Here: a = - 2 , b = 600 and C = 0

As a< 0, the parabola opens DOWNWARDS.

Here, x value is given as: $x = \frac{-b}{2a}$

Solving for the value of k similarly, we get:

$k = \frac{-b}{2a} = \frac{600}{2(-2)} = 150$

Thus the desired width = k = 150 meters

So, the desired dimensions of the plot is width 150 meters.

And length = 650 - 2k = 650 - 300 = 350 meters.

5 0

2 years ago

Suppose we are interested in analyzing the weights of NFL players. We know that on average, NFL players weigh 247 pounds with a

tigry1 [53]

Answer:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

Step-by-step explanation:

For this case we have the following data given:

$\bar X =237$ represent the sample mean

$\sigma = 47$ represent the population deviation

$n =30$ represent the sample size selected

$\mu_0 = 247$ represent the value that we want to test.

The standard error for this case is given by:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

For the 90% confidence the value of the significance is given by $\alpha=1-0.9 = 0.1$ and $\alpha/2 = 0.05$ so we can find in the normal standard distribution a quantile that accumulates 0.05 of the area on each tail and we got:

$z_{\alpha/2}= 1.64$

And the margin of error would be:

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

The confidence interval for this case would be given by:

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

Replacing into formula (b) we got:

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is lower than 247 pounds, the system of hypothesis would be:

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

P-value

Since is a left tailed test the p value would be:

$p_v =P(z$

Conclusion

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2 years ago

you are baking muffins for your class. there are 17 total students in your class and you have baked 5 muffins. write and solve a

Tresset [83]

For your first answer 2=x+5/17 your second answer is 29. This is because "x" is the number that you need to bake which is 29. Therefore, 31/17=2

4 0

3 years ago

Read 2 more answers

Plz help due today giving brainliest!

Artyom0805 [142]

Answer:

The answers are C, D, A, and B.

Step-by-step explanation:

Hope this helps :D

8 0

3 years ago