Answer:
Step-by-step explanation:
<em>Angles that are opposite from each other are going to be the same in this case.</em>
<em>Let's plug in 15 into x</em>
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Answer:
Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Step-by-step explanation:
Let x be the number of 20¢ stamps, then the number of 3¢ stamps is x + 9.
Mason has 56 total 49¢ and 20¢ stamps, then the number of 49¢ stamps is 56 - x.
Amounts:
- in 49¢:
cents; - in 20¢:
cents; - in 3¢:
cents.
Total amount:

- $23.55.
Hence,

Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Answer:
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
it's basically divided