Answer:
If line EF was dilated by a scale of 1/2 from the origin to get line E'F', then if line E'F' is dilated by a scale of 2 from the origin, EF is obtained. Also, the length of EF is double than the length of E'F'.
Dilation by a scale of 2 from the origin transforms point (x,y) into (2*x, 2*y)
E'(1,0) -> E(2,0)
F'(1, 3) ->F(2, 6)
length of E'F': 3
length of EF: 6
Step-by-step explanation:
12. Cos 60° = 8/c
0,5 = 8/c
0,5 c = 8
c = 16
D² = V16²-8²
= V256-64
=V192 = V16×12 = 4V12
= 4V4×3 = 8V3
13. Cos 30° = 6/b
V3/2 = 6/b
V3 b = 12
b = 12/V3
b/Sin B = a /sin A
b/Sin90° = 6/ sin 60°
<u>b</u> = <u> </u><u> </u><u> </u><u>6</u><u> </u><u> </u><u> </u>
1 V3/2
b× <u>V3</u> = 6
2
b = 6× 2/V3
= 12/V3
Let's solve your equation step-by-step
16.8-(-23.72)-31.3=x
Step 1:simplify both sides of the equation
16.8-(-23.72)-31.3=x
16.8+23.72+-31.3=x
(16.8+23.72+-31.3)=x (combine like terms)
9.22=x
9.22=x
Step 2: flip the equation
Answer: x=9.22
Answer:
(-6,4)
Step-by-step explanation:
The equations are:

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

Now we can solve for y:

So plugging in y = 4 into an equation and solving for x, we have:

So y = 4 corresponds to x = 6 & x = -6
The pairs would be
(6,4) & (-6,4)
<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>
Answer:
d) All of the above
Step-by-step explanation:
A one way analysis of variance (ANOVA) test, is used to test whether there's a significant difference in the mean of 2 or more population or datasets (minimum of 3 in most cases).
In a one way ANOVA the critical value of the test will be a value obtained from the F-distribution.
In a one way ANOVA, if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal.
This one way test is an omnibus test, it only let us know 2 or more group means are statistically different without being specific. Since we mah have 3 or more groups, using post hoc analysis to check, it may still be possible it may still be possible that two or more of the population means are equal.
The degrees of freedom associated with the sum of squares for treatments is equal to one less than the number of populations.
Let's say we are comparing the means of k population. The degree of freedom would be = k - 1
The correct option here is (d).
All of the above