Question a:
f(6) = (6)² + 2(6) + 8
f(6) = 36 + 12 + 8
f(6) = 56
Question b:
f(x+4) = (x+4)² + 2(x+4) + 8
f(x+4) = x² + 8x + 16 + 2x + 8 + 8
f(x+4) = x² + 10x + 32
Question c:
f(-x) = (-x)² + 2(-x) + 8
f(-x) = x - 2x + 8
He will mix some 20% solution and some 70% solution to make 60% solution.
Let x = number of liters of 20% solution.
Let y = number of liters of 70% solution.
He wants to make 50 liters of 60% solution, so
x + y = 50 First Equation
The amount of acid in x amount of 20% solution is 20% of x, or 0.2x
The amount of acid in y amount of 70% solution is 70% of y, or 0.7y
The amount of acid in 50 liters of 60% solution is 60% of 50 liters, or 0.6 * 50 = 30
Now we add the amounts of acid.
0.2x + 0.7y = 30 Second Equation
x + y = 50
0.2x + 0.7y = 30
-0.2x - 0.2y = -10
0.2x + 0.7y = 30
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0.5y = 20
y = 40
x + y = 50
x + 40 = 50
x = 10
Answer: He needs 10 liters of 20% solution and 40 liters of 70% solution.
Answer: 2t + -8
Step-by-step explanation: Let's simplify this problem using the distributive property.
The first thing we want to do is change this minus to plus a negative.
Now we can distribute or multiply this 2 times
each of the terms inside the set of parentheses.
So we get 2(t) + 2(-4) and this simplifies to 2t + -8.
2t + -8 is the same thing as 2t -8.
Answer:
x=6t+9 y=-8-1
Step-by-step explanation:
Answer:
x=84
Step-by-step explanation:
Add 4 on both sides
3=x/12-4
7=x/12
Multiply both sides by 12
(12)7=x/12(12)
84=x
Hope this helps! :)
