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mr Goodwill [35]
3 years ago
10

5x^2-(3xy-7x^2)+(5xy-12x^2) When x=-0.25, and y=4

Mathematics
2 answers:
prohojiy [21]3 years ago
5 0

5x^2-(3xy-7x^2)+(5xy-12x^2)=5x^2-3xy+7x^2+5xy-12x^2=2xy\\\\ 2\cdot(-0.25)\cdot4=-2

hichkok12 [17]3 years ago
5 0

Answer:

-2

Step-by-step explanation:

5x^2-(3xy-7x^2)+(5xy-12x^2)

5x^2-3xy+7x^2+5xy-12x^2

[(5x^2+7x^2-12x^2)=0]

-3xy+5xy= -3(-.25)(4)+5(-.25)(4)

-3(-.25)(4)+5(-.25)(4)= 3-5= -2

-2

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kaheart [24]

Hello from MrBillDoesMath!

Answer:   b = 4, h = 13

Discussion:

For a triangle with base b" and height "h, the area formula is

A=  (1/2)bh.

In our case A = 26, h = 5b-7, so

26 = (1/2) b (5b-7).  Multiply both sides by 2:

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5b^2 - 7b - 52 = 0.   This factors as follows:

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