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2 years ago

5x^2-(3xy-7x^2)+(5xy-12x^2) When x=-0.25, and y=4

Mathematics

2 answers:

prohojiy [21]2 years ago

5 0

$5x^2-(3xy-7x^2)+(5xy-12x^2)=5x^2-3xy+7x^2+5xy-12x^2=2xy\\\\ 2\cdot(-0.25)\cdot4=-2$

hichkok12 [17]2 years ago

5 0

Answer:

-2

Step-by-step explanation:

5x^2-(3xy-7x^2)+(5xy-12x^2)

5x^2-3xy+7x^2+5xy-12x^2

[(5x^2+7x^2-12x^2)=0]

-3xy+5xy= -3(-.25)(4)+5(-.25)(4)

-3(-.25)(4)+5(-.25)(4)= 3-5= -2

-2

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