Answer:
y = -5x + 5
Step-by-step explanation:
Let the equation of the line be: y = ax + b.
The given points should satisfy the equation.
Substituting the points in the equation we get the values of 'a' and 'b'.
The first point is: (1,0)
⇒ 0 = a(1) + b ⇒ 0 = a + b
⇒ b = -a
(2, -5) is another point. Substituting this we have:
-5 = a(2) + b = 2a - a = a
⇒ a = -5
⇒ b = -a = 5.
Therefore, the equation of the line becomes y = -5x + 5.
Answer:
2 ![\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D)
Step-by-step explanation:
Substitute the given values into the expression
2 (
+ (
)² ) + 5(
)
= 2 (
+
) + ![\frac{5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D)
= 2 (
) + ![\frac{5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D)
= 2 (
) + ![\frac{5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D)
=
+ ![\frac{10}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B4%7D)
= ![\frac{11}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B4%7D)
= 2 ![\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D)
Answer:
5
Step-by-step explanation:
The interquartile range is the 3rd quartile minus the 1st quartile. The 3rd quartile is 8 and the 1st quartile is 3.
8 - 3 = 5
Any specific formulas you are using ?